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RSB [31]
2 years ago
12

"Mindy has a piece of string that is 5 1/2yd long. She cuts it into pieces that are each 1/2 yd long. Solve the equation 5 1/2 =

1/2x to find out how many pieces of string, x, she gets. Show your work
Mathematics
1 answer:
Debora [2.8K]2 years ago
6 0

Answer:

Step-by-step explanation:

Mindy has a piece of string that is 5 1/2yd long. She cuts it into pieces that are each 1/2 yd long. Solve the equation 5 1/2 = 1/2x to find out how many pieces of string, x, she gets. Show your work

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ANEK [815]

Answer:

D)

Step-by-step explanation:

8 0
3 years ago
Twice a number subtracted from four times a number, added to 15.
galina1969 [7]
For twice a number we can use the variable x
For four times a number we can use the variable c

4c - 2x + 15

I believe this is correct although I'm not 100% sure
3 0
3 years ago
Assume that 63% of people are left-handed. If we select 5 people at random, find the probability of each outcome described below
mash [69]

Answer:

a. 0.9931

b. 0.3423

c. 0.3907

d. 0.2670

e. 3.15

f. 1.0796

Step-by-step explanation:

The probability of the variable that said the number of left-handed people follow a Binomial distribution, so the probability is:

P(x)=nCx*p^{x}*(1-p)^{n-x}

nCx is calculated as:

nCx=\frac{n!}{x!(n-x)!}

Where x is the number of left-handed people, n is the number of people selected at random and p is the probability that a person is left--handed. So P(x) is:

P(x)=5Cx*0.63^{x}*(1-0.63)^{5-x}

Then the probabilities P(0), P(1), P(2), P(3), P(4) and P(5) are:

P(0)=5C0*0.63^{0}*(1-0.63)^{5-0}=0.0069

P(1)=5C1*0.63^{1}*(1-0.63)^{5-1}=0.0590

P(2)=5C2*0.63^{2}*(1-0.63)^{5-2}=0.2011

P(3)=5C3*0.63^{3}*(1-0.63)^{5-3}=0.3423

P(x)=5C4*0.63^{4}*(1-0.63)^{5-4}=0.2914

P(x)=5C5*0.63^{5}*(1-0.63)^{5-5}=0.0993

Then, the probability P(x≥1) that there are some lefties among the 5 people is:

P(x≥1) = P(1) + P(2) + P(3) + P(4) + P(5)

P(x≥1) = 0.0590 + 0.2011 + 0.3423 + 0.2914 + 0.0993 = 0.9931

The probability P(3) that there are exactly 3 lefties in the group is:

P(3) = 0.3423

The probability P(x≥4) that there are at least 4 lefties in the group is:

P(x≥4) = P(4) + P(5) = 0.2914 + 0.0993 = 0.3907

The probability P(x≤2) that there are no more than 2 lefties in the group is:

P(x≤2) = P(0) + P(1) + P(2) = 0.0069 + 0.0590 + 0.2011 = 0.2670

On the other hand, the expected value E(x) and standard deviation S(x) of the variable that follows a binomial distribution is:

E(x)=np=5(0.63)=3.15\\S(x)=\sqrt{np(1-p)}=\sqrt{5(0.63)(1-0.63)}=1.0796

6 0
3 years ago
Which property is not used to simplify the following expression? (X+2) times 5-7=5(x+2)-7
STatiana [176]

i think it is a i am not sure


7 0
3 years ago
2/5;0.5 tell whether each pair shows equivalent number
Georgia [21]
2/5= 40%, so no, they are not equivalent numbers,<span />
4 0
3 years ago
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