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dem82 [27]
3 years ago
11

Br uh don’t even type “I can’t see the pic” Solve both problems and show ur work

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0

Answer:

1.22

53.08

Step-by-step explanation:

4. We can find the quarter circle, we can find the whole triangle, lets do that

The circle is, 1/4*(1)^2*pi, which is 1/4pi

The triangle is, 2 * 2 divided by 2, which is 2

2 - 1/4pi gives us the shaded part or

2 - 1/4*3.14

2 - 0.785 = 1.215 rounded to 1.22

5. The area of a cylinder is pir^2h. r is 10, h is 1.2

12pi cm^3

we have 20 m^3 which is 2000 cm^3

Let's divide,

2000/37.68 = 53.078, rounded gives us 53.08

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Solve y = mx + b for x
eimsori [14]
Y=mx+b
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m m

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8 0
3 years ago
A farmer can buy two types of plant​ food, mix A and mix B. Each cubic yard of mix A contains 35 pounds of phosphoric​ acid, 15
Nadusha1986 [10]

Answer:

The answer is below

Step-by-step explanation:

Given that the minimum monthly requirements are 840 pounds of phosphoric​ acid, hence:

35 pounds of phosphoric acid mix A + 14 pounds of phosphoric acid mix B ≥ 840 pounds of phosphoric​ acid

35x + 14y ≥ 840

The minimum monthly requirements are 540 pounds of nitrogen, hence:

15 pounds of nitrogen mix A + 18 pounds of nitrogen mix B ≥ 540 pounds of nitrogen

15x + 18y ≥ 540

The minimum monthly requirements are 768 pounds of potash, hence:

16 pounds of potash mix A + 64 pounds of potash mix B ≥ 768 pounds of potash

16x + 64y ≥ 768

Also, x ≥ 0 and y ≥0.

Therefore the equations are:

35x + 14y ≥ 840

15x + 18y ≥ 540

16x + 64y ≥ 768

x ≥ 0 and y ≥ 0

Plotting with geogebra gives the graph below.

The point are (0,60), (48,0), (18,15), (32,4)

7 0
3 years ago
Help me for 20 points
Radda [10]

Answer:

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Step-by-step explanation:

y=13-2x^2

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2=y + x^5

4 0
3 years ago
Read 2 more answers
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Y_Kistochka [10]

Answer:

:]

Step-by-step explanation:

3 0
3 years ago
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WILL GIVE BRANLIEST!!! Pls help! Determine the coordinates of the point on the straight line y=3x+1 that is equidistant from the
iren [92.7K]

Let , coordinate of points are P( h,k ).

Also , k = 3h + 1

Distance of P from origin :

d=\sqrt{h^2+k^2}

Distance of P from ( -3, 4 ) :

d=\sqrt{(h+3)^2+(k-4)^2}

Now , these distance are equal :

h^2+(3h+1)^2=(h+3)^2+(3h+1-4)^2\\\\h^2+(3h+1)^2=(h+3)^2+(3h-3)^2

Solving above equation , we get :

P=(\dfrac{16}{21},\dfrac{23}{7})

Hence , this is the required solution.

6 0
3 years ago
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