5 x : 8 = 7 : 2 Calculate the value of x

CORRECT ANSWER GETS A BRAINLIEST

Alex787 [66]

Answer:

B. N(c) = (c-20)/n

Step-by-step explanation:

Given

C(n) = 10n+20

we have to find the inverse of this function

we have to express n in terms of C(n)

C(n) = 10n+20

we have make n independent of n and remove any other term containing on the side of n

subtracting 20 from LHS and RHS

C(n) - 20 = 10n+20 - 20

C(n) - 20 = 10n

dividing LHS and RHS by 10

C(n)/10 - 20/10 = 10n/10

=> n = (C(n) - 20)/10

Now given in problem, N(c) is no of bushels picked

and c is the cost of apple

so in function n = C(n) - 20/10

we replace C(n) with c

and n with N(c)

and then we have

N(c) = (c-20)/n Answer

3 0

3 years ago

Write each number in standard form

ss7ja [257]

The first answer is 9130000

I had a similar worksheet but I got it done a while ago soooooo sorry

5 0

4 years ago

Can you guys do this ASAP, thanks will mark brainliest

dybincka [34]

Answer:

A) Graph an quadratic equation for a parabola (x being to the power of 2), and a linear equation. Examples would be y=x² and y=x.

B) Parabolas that share the same vertex can simply have another transformation done to them. For example: y= 5x² and y=3x².

C) A line that would pass through these would be any linear graph WITHOUT a 'b' value, so a y intercept of 0. An example would be y=5x.

5 0

3 years ago

Read 2 more answers

What is the result of substituting for y in the bottom equation y=x+3 y=x^2+2x-4

8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

Solution:

Given that,

$y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4 ----- eqn 2$

We have to substitute eqn 1 in eqn 2

$x + 3 = x^2 + 2x - 4$

$\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0$

$\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}$

$x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}$

$x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925$

$Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925$

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0

4 years ago

Find the x-intercepts of the parabola with vertex (1,20) and y-intercept (0,16).

Wewaii [24]

Answer:

Step-by-step explanation:

Since we are finding the x-intercepts, that implies that this is a parabola that opens either up or down as opposed to right or left. It would benefit us to know the equation of the parabola so we could factor it to find the roots (which are also known as the x-intercepts).

Here's what we know:

h = 1, k = 20, x = 0, and y = 20. Filling in the vertex form of a parabola is already halfway to factored, so we'll use that format as opposed to the standard form, which is

$y=ax^2+bx+c$ . The vertex form is