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kirill115 [55]
2 years ago
7

Are these ratios equivalent? 12 bouquets for every 20 corsages 9 bouquets for every 15 corsages?​

Mathematics
1 answer:
ohaa [14]2 years ago
4 0

Answer:

yes, they are

Step-by-step explanation:

3;5 = 6;10

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Help ASAP i have a few mins left
Semenov [28]
Sorry i didn’t understood the question
3 0
3 years ago
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A certain new type of business succeeds 60% of the time. Suppose that 3 such businesses open (where they do not compete with eac
ella [17]

Answer:

0.216

Step-by-step explanation:

Given that a certain new type of business succeeds 60% of the time.

3 such businesses   are tested for success.

Since these three businesses open (where they do not compete with each other, so it is reasonable to believe that their relative successes would be independent). we can say X no of successful businesses is Binomial

with p = 0.6 and n =3

Required probability

=The probability that all 3 businesses succeed is:

= P(X=3)\\= 0.6^3\\= 0.216

8 0
3 years ago
-3 + n = 6n + 22 ; Solve for n.
anygoal [31]

Answer:

-3 + n = 6n + 22

-1n on both sides

-3=5n+22

-22 on both sides

-25=5n

divided by 5

-5=n

Step-by-step explanation:

6 0
2 years ago
scott can reach 57 inches high. scott stands on box that is 16 inches high how many inches high can scott reach now?
kompoz [17]

Answer: 73 inches high

Step-by-step explanation: 57+16=73

4 0
3 years ago
What is the answer to (6+4)tothe3power-1tothe8power
Ipatiy [6.2K]

Hey there!

\huge\boxed{(6 + 4)^3 - 1^8}

\huge\boxed{= 10^3 - 1^8}

\huge\boxed{10^3}

\huge\boxed{= 10\times10\times10}

\huge\boxed{= 100\times10 }

\huge\boxed{= 1,000}

\huge\boxed{1^{8}}

\huge\boxed{= 1\times1\times1 \times 1 \times 1 \times 1 \times 1 \times 1}

\huge\boxed{= 1 \times 1 \times 1 \times 1}

\huge\boxed{= 1\times1}

\huge\boxed{= 1}

\huge\boxed{1,000 - 1}

\huge\boxed{= 999}

\huge\text{Answer: \textsf{999}}

\huge\text{Good luck on your assignment \& enjoy your day!}

~\huge\boxed{\frak{Amphitrite1040:)}}

8 0
2 years ago
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