Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
The answer to your question is 22 degrees Celsius. To figure out the problem, all you do is take the minutes( 58 and 2 and 35 sec.) and convert to seconds(3,480 and 145) Then divide 3,480 by 145 ,which equals 24. Then take 24 and add to the final temperature, which equals 22.
hopes this helps! <span />
Answer:
it is not a polynomial it has no degree either .. and we only classify polynomials in accordance with their degrees
