All categories

2 years ago

Pls help im like 5 hrs behind in math

Mathematics

1 answer:

choli [55]2 years ago

6 0

Answer:

The composite area is a total of 62 square inches.

Step-by-step explanation:

You're given three rectangles of different width and height. To find the correct answer, you need to find the sum of each rectangles' area.

first though we need to find the height of the middle rectangle. We are told the total height and the other two rectangles' heights, so we just need to subtract the others' heights from the total:

10 - (4 + 1.5)

10 - 5.5

= 4.5

So the middle rectangle is 4x4.5 inches, giving it an area of 18 square inches

The top one is 8x4 inches for a total of 32 square inches.

And the bottom one is 1.5x8 inches, for a total 12 square inches.

If we add them all up, that's 18 + 32 + 12 square inches, or 62 square inches.

You might be interested in

Solve for x.<br> 10 m<br> 42

kramer

Answer:

The measures of a pair of same-side exterior angles are 10w and 5v. ... Find the measure of angles 1-7 given that lines m and n are parallel and t is transversal. ... Solve for x. 120= 15x +5+ 22x +4. 120 = 37% +. 4. (X=3]. 6. Use the following figure, given that ... Find the measure of angle 1. m24 = 123, mZ1 = 2x, mZ2 = x +42.

Step-by-step explanation:

5 0

2 years ago

Sum term product factor quotients coefficients for 5x+12

Svetllana [295]

I tried I hope this helps in any kind of way

4 0

2 years ago

Which equation represents a parabola that has a focus of (0 0) and a directrix of y = 2

mel-nik [20]

ANSWER

$x ^{2} = - 4(y - 1).$

EXPLANATION

Since the parabola has the (0, 0) and the directrix at y=2.

The equation is of the form

${(x - h)}^{2} = - 4p(y - k)$

where (h,k) is the vertex.

The vertex is half way between the directrix and the focus.

The vertex will be at (0,1)

and is the distance from the vertex to the focus which is 1.

${(x - 0)}^{2} = - 4(1)(y - 1)$

$x ^{2} = - 4(y - 1)$

7 0

2 years ago

Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ

Georgia [21]

The y-intercept of a function is the point where the graph crosses the $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
The y-intercept is -13.5
The standard equation of the function is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

$\mathbf{x = 10}$

$\mathbf{x = -3}$

$\mathbf{x = -9}$

Equate the above points to 0

$\mathbf{x -10 = 0}$

$\mathbf{x +3 = 0}$

$\mathbf{x +9 = 0}$

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

$\mathbf{x -10 = 0}$

$\mathbf{x +3 = 0}$

$\mathbf{x +9 = 0}$

Multiply the above equations

$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}$

$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }$

Expand

$\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }$

$\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }$

Expand

$\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }$

Collect like terms

$\mathbf{x^3 + 12x^2 - 10x^2+ 27x - 220x - 270 = 0 }$

$\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }$

Replace 0 with y

$\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Hence, the standard form is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Read more about graphs and functions at:

brainly.com/question/18806107

3 0

2 years ago

as the schools sign language interpreter kiran gets paid 35.50 for every parent-teacher conference that he attends. He also gets

yKpoI14uk [10]

<u>The interpreter attended </u><u>22 parent-teacher conference</u><u> and </u><u>5 school related assembly</u>

To solve this problem, we would write out two set of linear equations.

The data given on this problem are

parent-teacher conference = $35.50
school related assembly = $42
The total number of engagements = 27

Let x represent the number of parent-teacher conference

let y represent the number of school related conference

<h3>Equations</h3><h3> $x+y = 27...equation (i)\\35.50(x)+42y=991...equation(ii)$ </h3>

From equation (i)

$x+y = 27\\x = 27-y...equation(iii)\\$

Put equation(iii) into equation (ii)

$35.50x+42y=991\\35.50(27-y)+42y=991\\958.50-35.50y+42y=991\\6.50y=991-958.50\\y=5$

Put y = 5 into equation 1

$x+y=27\\y = 5\\x+5=27\\x=27-5\\x=22$

From the above calculations, he attended 22 parent-teacher conference and 5 school related assembly.

Learn more on linear equations here;

brainly.com/question/4074386

8 0

2 years ago

Read 2 more answers