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2 years ago

Amir says the graph of y= x2 + 16 has -4 as a zero. Is Amir correct? Explain.

Mathematics

2 answers:

sukhopar [10]2 years ago

8 0

Answer:

Amir is wrong

Step-by-step explanation:

The function y = x² + 16 is positive for any value of x, hence the graph has no intersection with the x-axis and therefore has no real zero's.

If no zero's, -4 also can't be its zero.

Art [367]2 years ago

3 0

Answer:

Step-by-step explanation:

It's law of equations .The number of zeros is also equal to the highest degree of the polynomial/equation.

y=x^2+16 has 3 zeros
2 is for x and 1 is for y .

Hence 4 can't be a zero because it won't intercept the x axis.

Let's check

$\\ \sf\longmapsto (-4)^2+16=16+16=32\neq 0$

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k0ka [10]

The slant height of the right circular cone will be $l=2\sqrt5}$

<h3>What is slant height of cone? </h3>

The formula for the slant height of the cone is given as:

$l^2=r^2+h^2$

Here we have

r=2 units

h=4 units

By putting the values we will get

$l=\sqrt{4^2+2^2$

$l=\sqrt{16+4$

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2 years ago

Given f(x) = 4x^2 + 19x - 5 and g(x) = 4x^2 - x what is (f/g)(x)?

Free_Kalibri [48]

$( \frac{f}{g} )(x) = \frac{4 {x}^{2} + 19x - 5}{4 {x}^{2} - x} = \frac{(4x - 1)(x + 5)}{x(4x - 1)} = \frac{x + 5}{x}$

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3 years ago

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The area of a square is 36 square feet. each side of the square measures

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6 ft for each side, bc area is side times side, which 6x6=36

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A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function

dexar [7]

Here's our equation.

$h=-16t+64t+3$

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

$0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a} \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16} = \frac{64\±\sqrt{4096+192}}{32}$

$= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}$

So the ball will return to the ground at the positive value of $\boxed{\frac{8+\sqrt{67}}{4}}$ seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

$\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2$

$h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}$

8 0

3 years ago

Suppose the radius of a circle is 3 units what is the circumference

HACTEHA [7]

Answer:

$6\pi$ or approximately $18.85$ units

Step-by-step explanation:

The formula for finding the circumference of a circle is $C=2\pi r$ , where $C$ = circumference and $r$ = radius. In this case, $r=3$ , so after plugging that into $C=2\pi r$ , we get:

$C=2\pi r\\ = 2*\pi *3\\=6\pi$

Since $\pi$ is approximately $3.1415$ , $6\pi =6*3.1415=18.849$ , which rounds to $18.85$ . Therefore, the circumference of the circle is $6\pi$ , or approximately $18.85$ units. Hope this helps!

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