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2 years ago

Amir says the graph of y= x2 + 16 has -4 as a zero. Is Amir correct? Explain.

Mathematics

2 answers:

sukhopar [10]2 years ago

8 0

Answer:

Amir is wrong

Step-by-step explanation:

The function y = x² + 16 is positive for any value of x, hence the graph has no intersection with the x-axis and therefore has no real zero's.

If no zero's, -4 also can't be its zero.

Art [367]2 years ago

3 0

Answer:

Step-by-step explanation:

It's law of equations .The number of zeros is also equal to the highest degree of the polynomial/equation.

y=x^2+16 has 3 zeros
2 is for x and 1 is for y .

Hence 4 can't be a zero because it won't intercept the x axis.

Let's check

$\\ \sf\longmapsto (-4)^2+16=16+16=32\neq 0$

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