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Nata [24]
3 years ago
7

Amir says the graph of y= x2 + 16 has -4 as a zero. Is Amir correct? Explain.

Mathematics
2 answers:
sukhopar [10]3 years ago
8 0

Answer:

  • Amir is wrong

Step-by-step explanation:

The function y = x² + 16 is positive for any value of x, hence the graph has no intersection with the x-axis and therefore has no real zero's.

If no zero's, -4 also can't be its zero.

Art [367]3 years ago
3 0

Answer:

No

Step-by-step explanation:

It's law of equations .The number of zeros is also equal to the highest degree of the polynomial/equation.

  • y=x^2+16 has 3 zeros
  • 2 is for x and 1 is for y .

Hence 4 can't be a zero because it won't intercept the x axis.

Let's check

\\ \sf\longmapsto (-4)^2+16=16+16=32\neq 0

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Answer:

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Step-by-step explanation:

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<em>Comment on the problem</em>

Since you are given the base and height, we presume you are intended to use the formula above. You are also given all three side lengths. If you use the appropriate formula with those, you find the area is about 15.6 square inches. (The height of this triangle is actually closer to 5.2 inches.)

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3 years ago
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Answer:

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Step-by-step explanation:

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