All categories

3 years ago

Naruto was the ___ Hokage.

SAT

2 answers:

sladkih [1.3K]3 years ago

8 0

Answer:I think it is the Seventh Hokage.

Explanation:

Vilka [71]3 years ago

8 0

Answer: I never watched Naruto owo"

Explanation:

You might be interested in

A rectangle was altered by increasing its length by 10 percent and decreasing its width by p percent. If these alterations decre

valina [46]

Answer:

P=20

Explanation:

3 0

4 years ago

What condition best describes the heat flow from one object to another.

lapo4ka [179]

Heat can be transferred in three ways: by conduction, by convention, and by radiation. Conduction is transferred of energy from one molecule to another by direct contact.

4 0

3 years ago

How can you tell if an expression factors as (a + b)(a - b)?

LUCKY_DIMON [66]

Difference of two squares
it always results in a^2-b^2

8 0

3 years ago

At a football game, the ratio of filled seats to empty seats was 7 to 3. The capacity of the stadium is 70,580. How many seats w

UkoKoshka [18]

The number of seats in the stadium that were filled for the game is equal to 49,406 seats.

Let the filled seats be F.

Let the empty seats be E.

<u>Given the following data:</u>

Stadium capacity = 70,580.

Ratio of F to E = 7:3

Total ratio= 7 + 3 = 10

To determine the number of seats in the stadium that were filled for the game:

Mathematically, the number of filled seats in the stadium is given by this expression:

$F = \frac{7}{10} \times 70580\\\\F=0.7 \times 70580$

F = 49,406 seats.

Read more on ratio here: brainly.com/question/13513438

4 0

3 years ago

In a recent year, about 22% of Americans 18 years and older are single. What is the probability that in a random sample of 200 A

Pie

Using the normal approximation to the binomial, it is found that there is a 0.0107 = 1.07% probability that more than 30 are single.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

In this problem, the proportion and the sample size are, respectively, p = 0.22 and n = 200, hence:

$\mu = np = 200(0.22) = 44$

$\sigma = \sqrt{np(1 - p)} = \sqrt{200(0.22)(0.78)} = 5.8583$

The probability that more than 30 are single, using continuity correction, is P(X > 30.5), which is <u>1 subtracted by the p-value of Z when X = 30.5</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{30.5 - 44}{5.8583}$

Z = -2.3

Z = -2.3 has a p-value of 0.0107.

0.0107 = 1.07% probability that more than 30 are single.

More can be learned about the normal distribution at brainly.com/question/24663213

6 0

2 years ago