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garik1379 [7]
3 years ago
5

Lena skied downhill at a steady speed on a 3 mile slope she reached the bottom of the slope in 1/4 hour Lena wants to know her s

peed in miles per hour
Mathematics
1 answer:
gulaghasi [49]3 years ago
3 0

Answer:

first question : 3 / 1/4 ( 3 over 1/4 )

second : 3/1/4 = 12

Step-by-step explanation:

i dont know, i just got it right on iready

You might be interested in
4. If the sides of a square measure 9V3 units, then find the length of the diagonal.
Nitella [24]

Answer:

Step-by-step explanation:

To find the diagonal, use Pythagorean theorem,

diagonal² = side² + side²

                = (9√3)² + (9√3)²

                = 9²(√3)² + 9²(√3)²

                = 81*3 + 81*3

                = 243 + 243

                 = 486

diagonal = √486 = 22.05 units

7 0
3 years ago
The perimeters of two squares are in the ratio 2 : 4. The perimeter of
Bess [88]

Answer:

8

Step-by-step explanation:

2 : 4

8 : 16

8 0
3 years ago
2(x-3)=7x-31<br><br> 3x-2 (x+5)=-3+18<br><br> Please show your work
vredina [299]
2(x-3)=7x-31
2x-6=7x-31
-7x    -7x
----------------
-5x-6=-31
     +6   +6
--------------
-5x=-25
Divide by -5
x=5

3x-2(x+5)=-3+18
                     15
3x-2(x+5)=15
3x-2x-10=15
x-10=15               
 +10 +10
--------------
x=25
3 0
3 years ago
If you folded up the shape which cube would it make?
Margarita [4]
I believe that the answer is D.
5 0
3 years ago
Read 2 more answers
How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

5 0
3 years ago
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