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Dafna11 [192]
2 years ago
15

A bank loaned out $15,000, part of it at the rate of 7% per year and the rest at 17% per year. If the interest received in one y

ear totaled $2000, how much was loaned at 7%?
How much of the $15,000 did the bank loan out at 7%?
Mathematics
1 answer:
mel-nik [20]2 years ago
7 0

9514 1404 393

Answer:

  $5,500

Step-by-step explanation:

Let x represent the quantity loaned at 7%. Then the amount loaned at 17% is (15000-x), and the total interest is ...

  0.07x +0.17(15000 -x) = 2000

  -0.10x = -550 . . . . . . . . . collect terms, subtract 2550

  x = -550/-0.10 = 5500 . . . . divide by the coefficient of x

The bank loaned $5,500 at 7%.

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Step-by-step explanation:

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Corbin is selling cheese at the farmers’ market. One wheel of cheese has a diameter of 11 inches.
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Answer:

I. 94.99 in²

II. $0.23

Step-by-step explanation:

<u>Given the following data;</u>

Diameter of wheel = 11 inches

\pi = 3.14

Cost of wheel = $21.35

Radius, r = \frac {diameter}{2}

Radius, r = \frac {11}{2} = 5.5 \; inches

<em><u>Part A</u></em>

To find the area;

We know that a wheel is circular in nature. Thus, the area of a circle is given by the formula;

Area, A = \pi r^{2}

Substituting into the equation, we have;

Area, A = 3.14 * 5.5^{2}

Area, A = 3.14*30.25

<em>Area, A = 94.99 in²</em>

<em><u>Part B</u></em>

To find cost per square inch;

Cost \; per \; square \; inch = \frac {Cost \; per \; wheel}{Area \; of \; wheel}

Cost \; per \; square \; inch = \frac {21.35}{94.99}

<u>Cost per square inch = $0.23</u>

6 0
3 years ago
Using the quadratic formula, what are the solutions to x2 – 3x = -2?
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Step-by-step explanation:

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2 years ago
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frutty [35]

easy, 36/6=6

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7 0
3 years ago
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A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
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