How do I solve this equation? 4" id="TexFormula1" title="x + 8y = 20 \\ 2x + 4y = 4" alt="x + 8y = 20 \\ 2x + 4y = 4" align="absmiddle" class="latex-formula">
2 answers:
X = -8y + 20 2(-8y + 20) +4y = 4 -16y + 40 + 4y = 4 -12y +40=4 Subtract 40 from each side -12y= -36 Divide both by -12 y = 3 Plug Y=3 in to find x X + 8(3) = 20 X + 24 = 20 Subtract 24 x = -4
Answer:
Subtract x x from both sides of the equation. 8y=20−x 8 y = 20 - x. Divide each term by 8 8 and simplify.
Solve for x 2x-4y=4. 2x−4y=4 2 x - 4 y = 4. Add 4y 4 y to both sides of the equation. 2x=4+4y 2 x = 4 + 4 y. Divide each term by 2 2 and simplify.
You might be interested in
What is the inequality between these two fractions 1/2 2/4: answer =...so you would write it out like this 1/2=2/4
Answer:
Step-by-step explanation:
322+63
?=
0
385≠0
False
Answer:
128
Step-by-step explanation:
all angles of a triangle will always equal 180
so, we know 2 angles
180-40
140-1128
Answer:
(X<-25) or -oo, -25
Step-by-step explanation:
because max is -25