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Natali5045456 [20]
3 years ago
10

How do I solve this equation?

4" id="TexFormula1" title="x + 8y = 20 \\ 2x + 4y = 4" alt="x + 8y = 20 \\ 2x + 4y = 4" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
bixtya [17]3 years ago
7 0
X = -8y + 20
2(-8y + 20) +4y = 4
-16y + 40 + 4y = 4
-12y +40=4
Subtract 40 from each side
-12y= -36
Divide both by -12
y = 3
Plug Y=3 in to find x
X + 8(3) = 20
X + 24 = 20
Subtract 24
x = -4
ArbitrLikvidat [17]3 years ago
6 0

Answer:

Subtract x x from both sides of the equation. 8y=20−x 8 y = 20 - x. Divide each term by 8 8 and simplify.

Solve for x 2x-4y=4. 2x−4y=4 2 x - 4 y = 4. Add 4y 4 y to both sides of the equation. 2x=4+4y 2 x = 4 + 4 y. Divide each term by 2 2 and simplify.

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Answer:

36

Step-by-step explanation:

–12i × 3i

Multiply the numbers

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4 0
3 years ago
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Use these functions to answer the questions.
Elenna [48]
Part A
We have f\left(x\right)=\left(x+3\right)^2-1. To solve for the x-intercept, we set f(x) equal to 0.  That is
     \left(x+3\right)^2-1=0

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Take the square root of both sides, 
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To solve for the y-intercept, we set x=0. That is 
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Part B.
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Simplify
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Part C
We have h\left(t\right)=-16t^2+28t.
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4 0
3 years ago
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nikklg [1K]
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6 0
2 years ago
Question4..........................
belka [17]

Answer:

see explanation

Step-by-step explanation:

Given

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The negative is outside the bracket and is not squared, that is

= - \frac{2}{5} × \frac{2}{5}

= - \frac{2(2)}{5(5)} = - \frac{4}{25}

Given

\frac{5^3}{3} = \frac{5(5)(5)}{3} = \frac{125}{3}

4 0
3 years ago
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Nat2105 [25]

Answer:

I think the answer is graph A

8 0
3 years ago
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