Answer:
![y=-67.5[cos(\frac{\pi}{15}t)-1]](https://tex.z-dn.net/?f=y%3D-67.5%5Bcos%28%5Cfrac%7B%5Cpi%7D%7B15%7Dt%29-1%5D)
Step-by-step explanation:
We can start solving this problem by doing a drawing of London Eye. (See attached picture).
From the picture, we can see that the tourists will start at the lowest point of the trajectory, which means we can make use of a -cos function. So the function will have the following shape:
where:
A=amplitude
= angular speed.
t= time (in minutes)
b= vertical shift.
In this case:
A= radius = 67.5 m
where the frequency is the number of revolutions it takes every minute, in this case:
so:
and
b= radius, so
b=A
b=67.5m
so we can now build our equation:
which can be factored to:
You can see a graph of what the function looks like in the end on the attached picture.
Answer: C 20
Explanation: Plug in 2 for k.
2^2 - (2-10) + 4(2) = 20
D. 1/4 i think sorry if i’m wrong
Answer: Focus = (-2, 3)
<u>Step-by-step explanation:</u>
First let's find the vertex. We do that by finding the Axis-Of-Symmetry:
Then finding the maximum by inputting x = -2 into the given equation:
The vertex is: (-2, 4)
Now let's find p, which is the distance from the vertex to the focus:
The vertex is (-2, 4) and p = -1
The focus is (-2, 4 + p) = (-2, 4 - 1) = (-2, 3)
Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
