Step-by-step explanation:
in this condition we are given simple interest time and rate
so principal is missing so we should use the formula of principal that is
P=I×100/T×R
but we should convert that month in to years and we convert it by dividing it by 12.
Complete Question
A dog weighs 2 pounds less than 3 times the weight of a cat. The dog weighs twenty two more pounds than the cat.
Write and solve an equation to find the weights of the cat and the dog.
Answer:
Weight of cat = x = 12 pounds
Weight of Dog = y = 34 pounds
Step-by-step explanation:
Let's represent:
Weight of cat = x
Weight of Dog = y
A dog weighs 2 pounds less than 3 times the weight of a cat.
y = 3x - 2........ Equation 1
The dog weighs twenty two more pounds than the cat
y = x + 22....... Equation 2
The equation is given as:
y = y
3x - 2 = x + 22
Collect like terms
3x - x = 22 + 2
2x = 24
x = 24/2
x = 12 pounds
Solving for y using any of the equations:
y = 3x - 2
y = 3 × 12 - 2
y = 36 - 2
y = 34 pounds
Therefore:
Weight of cat = x = 12 pounds
Weight of Dog = y = 34 pounds
Answer: 0.14
Step-by-step explanation:
Given: Mean : 
In minutes , Mean : 
The exponential distribution function with parameter 
is given by :-
The probability of waiting more than 30 seconds i.e. 0.5 minutes is given by the exponential function :-
![P(X\geq0.5)=1-P(X\leq0.5)\\\\=1-\int^{0.5}_{0}4e^{-4t}dt\\\\=1-[-e^{-4t}]^{0.5}_{0}\\\\=1-(1-e^{-2})=1-0.86=0.14](https://tex.z-dn.net/?f=P%28X%5Cgeq0.5%29%3D1-P%28X%5Cleq0.5%29%5C%5C%5C%5C%3D1-%5Cint%5E%7B0.5%7D_%7B0%7D4e%5E%7B-4t%7Ddt%5C%5C%5C%5C%3D1-%5B-e%5E%7B-4t%7D%5D%5E%7B0.5%7D_%7B0%7D%5C%5C%5C%5C%3D1-%281-e%5E%7B-2%7D%29%3D1-0.86%3D0.14)
Hence, the probability of waiting more than 30 seconds = 0.14
Answer:
9x^2+24x+16
Step-by-step explanation:
It would be A, because her annual premium rate is $3.25 for every $1,000. So 3.25x130=$422.50
