All categories

1 year ago

Please help pic provided below what can you tell about the mean of each distribution?

Mathematics

1 answer:

Roman55 [17]1 year ago

6 0

The information illustrated that A. there is a small difference in the mean number of stray cats placed in homes buy a new lease on life animal clinic each week and the mean number of stray cats placed in homes by no raft staff animal hospital each week.

A mean or average is the ratio of the sum of observations to the number of observations.

For the first case:

Mean = (13*5 + 14*10 + 15*19 + 16*13 + 17*4)/75 = 10.21

For the second case:

Mean =(3*2 + 4*10 + 5*21 + 6*11 + 7*5 + 8*3)/33 = 10.48

Therefore, it should be noted that there is a small difference in the mean number of stray cats placed in homes buy a new lease on life animal clinic each week and the mean number of stray cats placed in homes by no raft staff animal hospital each week.

Learn more about mean on:

brainly.com/question/1136789

#SPJ1

You might be interested in

Ali bought 212 pounds of ground turkey at $2.50 per pound and 314 pounds of ground beef at $3.20 per pound.

den301095 [7]

Answer:

Step-by-step explanation:

the total cost for this question is $12.10.

let me know if this helped.

6 0

2 years ago

Find the equation of the line through (0,4) perpendicular to the line y = 3x

Rufina [12.5K]

Answer:

$y = - \frac{1}{3} x + 4$

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

The product of the gradients of perpendicular lines is -1.

Gradient of given line= 3.

(Gradient of line)(3)= -1

3m= -1

m= $- \frac{1}{3}$

subst. m= $- \frac{1}{3}$ into the equation:

$y = - \frac{1}{3} x + c$

To find the value of c, substitute a coordinate.

When x=0, y=4,

$4 = - \frac{1}{ 3} (0) + c \\ 4 = c \\ c = 4$

Thus the equation of the line is $y = -\frac{1}{3} x + 4$ .

3 0

3 years ago

When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode

yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are central tendency measures in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a normal distribution, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a distribution is not symmetrical, we say it is skewed. The skewness is a measure of the asymmetry of the distribution. In this case, the mean, median and mode are not the same, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (negative skew), or greater than them (positive skew), or approximately equal than the median but much greater than the mode (a variation of a positive skew case).

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a mound-shaped symmetrical distribution, it resembles the normal distribution and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, they are all approximately equal. So, the general relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, considering they have similar characteristics of the normal distribution, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0

2 years ago

Which solid figure does this net represent? A) Eliminate B) square pyramid C) triangular prism D) triangular pyramid

vampirchik [111]

It represent a square pyramid

6 0

3 years ago

X-25/14=6/7 find the solution

Lubov Fominskaja [6]

$x= \frac{6}{7} + \frac{25}{14} = \frac{12+25}{14} = \frac{37}{14}$

4 0

3 years ago