Question

F(x)8x^2 find its inverse

Answer 1

Answer:

$f^{-1}(x)=\frac{1}{2}\sqrt{\frac{x}{2}}$

Step-by-step explanation:

Given:

The function is given as;

$f(x)=8x^2$

In order to find the inverse, the steps to be followed are:

Step 1: Replace $f(x)$ by $y$. This gives,

$y=8x^2$

Step 2: Switch 'y' by 'x' and 'x' by 'y'. This gives,

$x=8y^2$

Step 3: Solve for 'y'.

Dividing both sides by 8, we get:

$\frac{x}{8}=\frac{8y^2}{8}$

$\frac{x}{8}=y^2$ or

$y^2=\frac{x}{8}$

Taking square root on both sides, we get:

$\sqrt{y^2}=\sqrt{\frac{x}{8}}$

$y=\frac{1}{2}\sqrt{\frac{x}{2}}$

Now, we replace 'y' by $f^{-1}(x)$.

Therefore, the inverse of the given function is:

$f^{-1}(x)=\frac{1}{2}\sqrt{\frac{x}{2}}$