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gizmo_the_mogwai [7]
3 years ago
15

Your school is planning a field trip to the zoo. There are two different bus companies that the school can

Mathematics
1 answer:
inysia [295]3 years ago
3 0

Answer:

For Company A 15 students will be able to go. For company B 21 students will be able to go.

Step-by-step explanation:

Company A 15 x 7 = 105

Company B 21 x 5 = 105

The total amount of money each company will get is $105.

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When the polynomial is written in standard form, what are the values of the leading coefficient and the constant? 5x + 2 - 3x^2
earnstyle [38]
Leading coefficient = -3
Constant = 2

When you order them in standard form, you need to put them in ascending order of the exponents. Therefore the -3x^2 would come first, which makes the number attached (-3) the lead coefficient. 

Also, since the number (2) without an x attached would be last (due to the power of x technically being 0), than that is the constant. 
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3 years ago
Please help! whats 15 divided by 12
katrin2010 [14]

Answer:

1.25

Step-by-step explanation:

4 0
3 years ago
Bob raises Guinea Pigs and Chinchillas on his beachfront oasis. There are a total of 60,005 animals at the oasis. The number of
raketka [301]
Let named variables as you said g- guinea pigs and c- chinchillas
System of equation is:

First is:   c+ g = 60,005 
Second is:   c= 2g+5

When we replace second in first we get:

2g+5+g = 60,005 => 3g+5= 60,005 => 3g= 60,000

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When this result we replace in the second equation we get

c= 2 * 20,000 +5= 40,000+5 = 40,005

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Good luck!!!!




6 0
3 years ago
write the eqaution in slope intercept form of the line that has a slope of 2 and contains the point (4,2)
GalinKa [24]
Slope intercept form:
y=mx+b
m=slope
b=y-intercept:

We Know the slope (m=2)and we have a point (4,2) then:
x₀=4
y₀=2
we have to find "b"
y=mx+b
2=2(4)+b
8+b=2
b=2-8
b=-6

Therefore:
if b=-6 and m=2; the equation in slope intercept form would be:
y=2x-6

<span>Answer: y=2x-6</span>
3 0
3 years ago
How do I verify #15 using fundamental trig identities?
expeople1 [14]

We start with the more complicated side which is the left side, and show that, on using some trigonometric identities, we will get the term on the right side .

\frac{sin \theta + tan \theta}{1+cos \theta}

Using Quotient identity for tangent function, we will get

\frac{sin \theta+ \frac{sin \theta}{cos \theta}}{1+cos \theta}

\frac{sin \theta cos \theta + sin \theta}{cos \theta(1+cos \theta)}

Taking out sine function from the numerator

=\frac{sin \theta(1+cos \theta)}{cos \theta(1+cos \theta)}

Cancelling the common term of numerator and denominator

=\frac{sin \theta}{cos \theta} = tan \theta

7 0
3 years ago
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