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77julia77 [94]
3 years ago
5

Travis just started high school and he wants to manage his time wisely. He schedules 3/2 hours each day for homework, 1/2 of an

hour each day for chores at home, and 17/2 hours each day for sleep. How many hours each day are scheduled for these activities?
Mathematics
1 answer:
lord [1]3 years ago
3 0

hw: 3/2hrs = 3×30 = 90mins

chores: 1/2hr = 1×30 = 30mins

sleep: 17/2hrs = 17×30 = 510mins

90+30+510=630mins=10.5hrs/day

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Is the relationship between the variables in the table a direct variation, an inverse variation, or neither? If it is a direct o
inn [45]

Answer: neither direct variation nor inverse variation.


Explanation:


1) The relation between two variables, y and x, is a direct variation if and only if the quotient between them, y/x, is constant. This is: y / x = k or, equivalently, y = kx.


Note that if y / x is constant, x / y is also constant.


In a direct variation, when x increases, y increases, and when x decreases, y decreases.


2) The relation between two variables, y and x, is an inverse variation if and only if their product, y×x is constant. This is: y × x = k or, equivalently y = k /x or x = k / y.


In an inverse variation when one of the variables increases the other decreases.


3) Writhe the given table and study whether the conditions for direct or inverse variation are met:

x      y              y/x                             y×x

-6    -72           -72/(-6) = 12             (-6)(-72) = 432

-4    -47           -47 / (-4) = 11.75       (-4)(-47) = 188

-3    -36           -36 / (-3) = 12           (-3)(-36) = 108

1       12             12 / 1 = 12                (1)(12) = 12


Conclusions;


a) Since neither y / x nor y×x have the same result for every pair, the relation is neither direct nor inverse.


b) Note that if the third pair were (-4, -48) instead of (-4, -47), y / x would be 12, which make a direct variation. In this case the function that modeled it would be:

         y = 12x.

8 0
3 years ago
Find the distance between each pair of points.<br> 3) (6, -2), (8, -3)<br> 4) (7,-8), (-8, 2)
castortr0y [4]

Answer:

3) \sqrt{5}

4)5\sqrt{13}

Step-by-step explanation:

distance between two points:

d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}

we have:

3) (6, -2), (8, -3)

x_{1} = 6

y_{1} =-2

x_{2} = 8

y_{2} =-3

so we have:

d =\sqrt{(8-6)^{2}+ (-3-(-2))^{2}}\\\\d =\sqrt{(2)^{2}+ (-1)^{2}}\\\\d = \sqrt{4+ 1}\\\\d=\sqrt{5}

4) (7,-8), (-8, 2)

x_{1} = 7

y_{1} =-8

x_{2} =-8

y_{2} =2

d =\sqrt{(-8-7)^{2}+ (2-(-8))^{2}}\\\\d =\sqrt{(-15)^{2}+ (10)^{2}}\\\\d = \sqrt{225+ 100}\\\\d=\sqrt{325}\\\\d=5\sqrt{13}

3 0
3 years ago
To secure your financial future, you must have some source of income. While income can be earned in a variety of ways, most peop
VladimirAG [237]

Answer:

You would also need to know for how many hours each day would you be working.

5 0
3 years ago
The distance between the point (2,1,1) and the plane x-2y=5 is​
Eduardwww [97]

The given plane has normal vector

x-2y=5\implies\mathbf n=\langle1,-2,0\rangle

Scaling <em>n</em> by a real number <em>t</em> gives a set of vectors that span an entire line through the origin. Translating this line by adding the vector <2, 1, 1> makes it so that this line passes through the point (2, 1, 1). So this line has equation

\mathbf r(t)=\langle1,-2,0\rangle t+\langle2,1,1\rangle=\langle 2+t, 1-2t, 1\rangle

This line passes through (2, 1, 1) when <em>t</em> = 0, and the line intersects with the plane when

x-2y=5\implies(2+t)-2(1-2t)=5\implies5t=5\implies t=1

which corresponds the point (3, -1, 1) (simply plug <em>t</em> = 1 into the coordinates of \mathbf r(t)).

So the distance between the plane and the point is the distance between the points (2, 1, 1) and (3, -1, 1):

\sqrt{(2-3)^2+(1-(-1))^2+(1-1)^2}=\boxed{\sqrt5}

7 0
3 years ago
Simplify the following expression. 16x^6-12x^4+2x^2 / _2x^2
mojhsa [17]
6x^2/2x^2
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5 0
3 years ago
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