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3241004551 [841]
3 years ago
12

Finish the formula sequence ,15,11,7,3​

Mathematics
1 answer:
pickupchik [31]3 years ago
3 0

Answer:

15,11,7,3,-1,-5,-9,-13, etc

Step-by-step explanation:

-4 every time

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The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,
Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

If the mean number of arrivals is 10

This means that \mu = 10

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is P(X \leq 10)

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045

P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045

P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023

P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076

P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189

P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378

P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631

P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901

P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126

P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251

P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831

58.31% probability that there are no more than 10 arrivals.

8 0
3 years ago
I need help no one helps me never
slavikrds [6]
I believe the answer is D
5 0
3 years ago
A hardware store owner is replenishing his stock of base paint for an upcoming home improvement sale. He conducted a survey to d
antiseptic1488 [7]

Solution:

                       Matte Satin    Glossy Total

Homeowners 0.08 0.20 0.24 0.52

Contractors 0.04 0.26 0.18         0.48

Total         0.12         0.46 0.42   1

Approximately what percentage of contractors prefer the glossy finish?

Answer: Percentage of contractors who prefer the glossy finish is:

\frac{0.18}{0.48}=0.375
 or 37.5\%

Therefore, the option D. 37.5% is correct

6 0
3 years ago
Read 2 more answers
The number -3 can be classified as which of the following?
sp2606 [1]

<u>Answer</u>:

-3 is an integer, rational number and real number , so correct option id D) that is all of the above.

<u>Explanation:</u>

Integer is all natural number  that a 1 , 2 , 3 , 4 ……. And zero and negative of natural numbers like -1 , -2 , -3 , - 4 ……. So -3 is an integer.

Rational number is the number which can be represented in the form of p/q where p and q are integers and q ≠ 0 . As -3 can be represented as (-3)/1 . hence -3 is also a rational number.

Real number is all number which can be represented on number line. All integers and rational numbers are real numbers . so -3 is also a real number.

Hence as -3 is an integer, rational number and real number , so correct option id D) that is all of the above.

5 0
4 years ago
Can someone help me I’ll Mark brainliest I been struggling with this one :(
mariarad [96]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
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