All categories

3 years ago

I need to know whether the relation is a function.

Mathematics

1 answer:

andrew11 [14]3 years ago

4 0

Answer:

Yes

Step-by-step explanation:

Yes, actually. If we graph the data table we see that the function actually passes the vertical line test. Despite the same output occurring for different inputs, a single x-value does not have multiple y-values, which would mean it <em>wasn't</em> a function.

Hope this helps!

You might be interested in

Help:) Factor f(x) = 4x^3+ 23x^2- 70x + 16 into linear factors given that - 8 is a zero of f(x).

Charra [1.4K]

Answer:

(x + 8)(x - 2)(4x - 1)

Step-by-step explanation:

Given that x = - 8 is a zero then (x + 8) is a factor

Divide f(x) by (x + 8) using Synthetic division

- 8 | 4 23 - 70 16

↓ - 32 72 - 16

---------------------------------

4 - 9 2 0

Quotient = 4x² - 9x + 2 = (x - 2)(4x - 1)

Thus

f(x) = (x + 8)(x - 2)(4x - 1)

8 0

3 years ago

Please help me. right answer will get brainliest

Harman [31]

Answer:

I attached the answers :)

Step-by-step explanation:

hope this helps :)

(Its a bit messy becuz i used a mouse to write, sry about that)

8 0

3 years ago

8h=28 how do you solve this

Rashid [163]

Answer:

h=3.5

Step-by-step explanation:

divide 28 by 8

hope I helped

5 0

3 years ago

Read 2 more answers

Find the five-number summary for the given data. Min Q1 Q2 Q3 Max

Aleonysh [2.5K]

Answer with Step-by-step explanation:

16 19 21 26 27 29 34 35 35 39 40 41 42 50 50 52 57 60 75 76 78 81 84

the data is already arranged in ascending order

Min=16

Max=84

The quartiles for the odd set of data is given by

$Qi=\dfrac{i(n+1)}{4}\ th\ term$

where n is the number of elements

Here, n=23

$Q1=\dfrac{(23+1)}{4}\ th\ term$

Q1=6 th term

Q1=29

Q2=12 th term

Q2=41

Q3=18 th term

Q3=60

Hence, five-number summary for the given data is:

Min Q1 Q2 Q3 Max

16 29 41 60 84

8 0

3 years ago

Factor c^2 −64. Is this a special product?<br> PLS HELP

laila [671]

C^2-64 is a square roots factoring one. you take the square root of c^2 which is c and then the square root of 64 which is 8 or -8 so the answer is (c-8)(c+8). and it is a special product

8 0

2 years ago