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Kazeer [188]
3 years ago
7

Why are there more producers than nutrients? (In an ecosystem, more specifically, regarding trophic levels.)

Biology
1 answer:
Anna71 [15]3 years ago
3 0

Explanation:

any step in a nutritive series, or food chain, of an ecosystem dead organisms and waste materials into nutrients usable by the producers

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I believe A is the correct answer
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Binding of an eosinophil to an antibody-coated parasitic worm involves binding of the antibody's stem region to a(n) ______.
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Answer:

plasma membrane protein on the eosinophil's surface

Explanation:

Eosinophils sometimes called acidophils are a part of the immune system. The responsible for fighting viral infections and parasites. Eosinophils expresses IgE- binding protein and a protein toxin, cathepsin on the plasma memberane surface along with the SNARE complexes.

Therefore, binding of an eosinophil to an antibody-coated parasitic worm involves binding of the antibody's stem region to a plasma membrane protein on the eosinophil's surface.

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3 years ago
A fossil is discovered that has only 12.5% of the carbon-14 that it would have had originally (when the animal was alive). If th
mariarad [96]

Answer:

The fossil is 17,100 years old.

Explanation:

The decay equation:

\frac{dN}{dt}\propto -N

\Rightarrow \frac{dN}{dt}= -\lambda N

\Rightarrow \frac{dN}{N}= -\lambda dt

Integrating both sides

\Rightarrow \int\frac{dN}{N}= \int-\lambda dt

\Rightarrow ln |N|=-\lambda t+c

When t=0, N=N_0 = initial amount

ln |N_0|=-\lambda .0+c

\Rightarrow ln |N_0|=c

\therefore ln |N|=-\lambda t+ln|N_0|

\Rightarrow ln |N|-ln|N_0|=-\lambda t

\Rightarrow ln |\frac {N}{N_0}|=-\lambda t

\Rightarrow \frac {N}{N_0}=e^{-\lambda t}

\Rightarrow N=N_0e^{-\lambda t}

The decay equation is

N=N_0e^{-\lambda t}

Given that,

The half life of carbon - 14 is 5700 years.

For half life, N=\frac{1}{2} N_0

To find the value of  \lambda, we need to put the value of N and t in the decay equation.

\frac12N_0=N_0e^{-\lambda \times 5700}

\Rightarrow \frac12=e^{-\lambda \times 5700}             [ Divided N_0 both sides]

Taking ln both sides

\Rightarrow ln| \frac12|=ln|e^{-\lambda \times 5700}|

\Rightarrow ln| \frac12|={-\lambda \times 5700}

\Rightarrow \lambda= \frac{ln| \frac12|}{-5700}

\Rightarrow \lambda= \frac{ln|1|-ln|2|}{-5700}             [ ln|\frac mn|= ln |m|-ln |n|]

\Rightarrow \lambda= \frac{ln|2|}{5700}                      [ln 1= 0]

The fossil has only 12.5% of the carbon carbon-14 that it would have had originally.

So, N=\frac{12.5}{100} N_0

Then,

\frac{12.5}{100} N_0=N_0e^{-\frac{ln|2|}{5700}t

\Rightarrow \frac{12.5}{100} =e^{-\frac{ln|2|}{5700}t

Taking ln both sides

\Rightarrow ln|\frac{12.5}{100} |=ln|e^{-\frac{ln|2|}{5700}t}|

\Rightarrow ln|\frac{12.5}{100} |={-\frac{ln|2|}{5700}t}

\Rightarrow t=\frac{ ln|\frac{12.5}{100}|} {-\frac{ln|2|}{5700}}

\Rightarrow t=\frac{ ln|\frac{12.5}{100}|\times 5700} {-{ln|2|}}

\Rightarrow t=17,100

The fossil is 17,100 years old.

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4 years ago
Which of the following best explains how the structure of ATP helps provide energy to the cell?
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ATP contains energy in the chemical bonds between its phosphate groups, <span>best explains how the structure of ATP helps provide energy to the cell.</span>
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A narrow strip of land connecting two larger land bodies is known as a(n):
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B. Isthmus
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