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alina1380 [7]
3 years ago
13

Is the relationship shown by the data linear?if it is,model the data with an equation

Mathematics
1 answer:
Kazeer [188]3 years ago
6 0
Yes, yes, and yes.
y=4x-5
y=x+6.5
y=-2x+?
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E
Allushta [10]

Answer:

Step-by-step explanation:

We can use Hypotenuse Theorem for this:

For triangle ABC,

AC²=CB²+BA²

9²=CB²+3²

Switch the sides

-CB²=3² -9²

-CB²= 9-81

-CB²= -72

the signs cut each other

CB²=72

the square changes sides

CB=√72

CB= 8.49 cm

Now triangle CBD

We have the length of CB but not the other two whereas we have the angle

It will be sin

As we know sin= O/H

Here O is CB whereas H is CD

Put the values

sin 50= 8.49/H

H= 8.49 ÷sin 50

Calculate

H=11.1 cm

As we know H is CD so CD is 11.1 cm

Hope it helps

8 0
3 years ago
Test the convergence of 011xx dx .
Slav-nsk [51]

Step-by-step explanation:

eggfdddfgggfseeedhhggh

6 0
3 years ago
What is the degree Celsius temperature of a person with 95 degree Fahrenheit fever​
My name is Ann [436]

Answer:

35° Celsius

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
At a local election there were two propositions on the ballot, R and S. Twice as many voters voted "yes" for R as for S. If the
Over [174]

Answer:

c. 130

Step-by-step explanation:

Let call B the quantity of voters who voted yes for both propositions.

From the question we know that twice as many voters voted "yes" for R as for S, that can be written as the following equation:

R+B=2(S+B)

Where R is the number who voted "yes" for R but "no2 for S and S is the number who voted "yes" for S but "no" for R.

Replacing R by 750 and S by 310 and solving for B, we get:

750+B=2(310+B)

750+B=620+2B

2B-B=750-620

B=130

So, 130 voters voted yes for both propositions

7 0
3 years ago
If log a = x and log b = y, then log (ab2) equals
mylen [45]

Answer:

The answer for log(ab²) is x + 2y.

Step-by-step explanation:

You have to apply Logarithm Law,

log(a)  +   log(b) \:  ⇒ \:  log(a \times b)

log( {a}^{n} )  \: ⇒ \: n log(a)

In this question, you have to seperate it out :

log(a {b}^{2} )  =  log(a)  +  log( {b}^{2} )

log( {b}^{2} )  = 2 log(b)

let \:  log(a)  = x

let log(b)  = y

log(a {b}^{2} )  =  log(a)  + 2 log(b)

log(a {b}^{2} )  = x + 2y

3 0
3 years ago
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