1. a b c
2. a b c
3. a b c
4. a b c
5. a b c
then she eliminated 1 choice in 1 and 2, say as follows
1. b c
2. a b
3. a b c
4. a b c
5. a b c
Probability of answering correctly the first 2, and at least 2 or the remaining 3 is
P(answering 1,2 and exactly 2 of 3.4.or 5.)+P(answering 1,2 and also 3,4,5 )
P(answering 1,2 and exactly 2 of 3.4.or 5.)=
P(1,2,3,4 correct, 5 wrong)+P(1,2,3,5 correct, 4 wrong)+P(1,2,4,5 correct, 3 wrong)
also P(1,2,3,4 c, 5w)=P(1,2,3,5 c 4w)=P(1,2,4,5 c 3w )
so
P(answering 1,2 and exactly 2 of 3.4.or 5.)=3*P(1,2,3,4)=3*1/2*1/2*1/3*1/3*2/3=1/4*2/9=2/36=1/18
note: P(1 correct)=1/2
P(2 correct)=1/2
P(3 correct)=1/3
P(4 correct)=1/3
P(5 wrong) = 2/3
P(answering 1,2 and also 3,4,5 )=1/2*1/2*1/3*1/3*1/3=1/108
Ans: P= 1/18+1/108=(6+1)/108=7/108
1. First I turned the fractions into decimals, just to make things easier for me.2. That gave me => (.25x)+(.75)+(.375)=(3.25)
3. Then, I combined like terms and move my equation around; so, that gave me (.25x) = (3.25) - (.75) - (.375) and when I solve the right side of the equation it gives me
(.25x) = (2.125)
4. After combining like terms and simplifying (the way I did in step 3), I will divide both sides by .25, to get the value of X alone; so, my equation then looks like => x=8.5
The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120
I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (
brainly.com/question/5761449)
No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120
(At least one car probability) is the opposite of (no car probability) In this case, the easier way is
100% - (no car probability) = 120/120 - 24/120= 96/120
One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability)
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120
One car probability = (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
Answer:
Step-by-step explanation:
1. Substitute p for 5p+4
2. 5p+4-11
3. 5p-7
