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3 years ago

Please show steps it help help alot

Mathematics

1 answer:

ss7ja [257]3 years ago

6 0

The Answer is in the attached file, I'm sorry if I can't write it on laptop, hope this helps man! :) and tell me if it's correct or wrong when your teacher see's it.

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What is 2.64 as a percent

Gala2k [10]

264 because you move the decimal 2 times to the right

5 0

3 years ago

At the start of the month, the value of an investment was $73.42. By the end of the month, the value of the investment changed b

Aleonysh [2.5K]

Answer:

0.8%.

Step-by-step explanation:

Given:

At the start of the month, the value of an investment was $73.42.

By the end of the month, the value of the investment changed by a loss of $13.53.

Question asked:

What was the value, in dollars, of the investment at the end of the month?

What was the percent loss?

Solution:

At the start of the month, the value of an investment = $73.42.

Loss = $13.53.

The value, of the investment at the end of the month = The value of an investment at the start of the month - loss

The value, of the investment at the end of the month = $73.42 - $13.53

= $59.89

Thus, the value, of the investment at the end of the month is $59.89.

Now, we will find percent loss:-

$Percent\ loss = \frac{Loss}{value\ of \ investment\ at \ start}$

$=\frac{59.89}{73.42} \\=0.81\%$

Thus, percent loss on investment by the end of the month is 0.8%.

7 0

3 years ago

Which equation is equivalent to y-1= 5(x+2) ?

Agata [3.3K]

Step-by-step explanation:

We can simply by opening the brackets ,

=> y - 1 = 5( x - 2 )

=> y - 1 = 5x - 10

=> y - 5x = -9

=> 5x - y + 9 = 0

8 0

3 years ago

The amount of time that a surveillance camera will run without having to be reset is a random variable having the exponential di

Evgesh-ka [11]

Answer: The required time is 0.743.

Step-by-step explanation:

Since we have given that

$\lambda=0.02$

We need to find the time above which is 68% of the cameras have to be reset.

So, exponential distribution would be

$f(x)=0.02e^{-0.02}$

So, it becomes,

$P(X$

Hence, the required time is 0.743.

8 0

4 years ago

Read 2 more answers

Maria has recently retired and requested an extra $444.00 per year in income. She has $ 5400 to invest in an A-rated bond that

Dimas [21]

Answer:

$2400 in A rated bond and $3000 in B rated bond.

Step-by-step explanation:

We have been given that Maria has recently retired and requested an extra $444.00 per year in income.

We can represent this information in an equation as:

$A+B=5400...(1)$

She has $5400 to invest in an A-rated bond that pays 10% per annum or a B-rated bond paying 6% per annum.

$0.10A+0.06B=444...(2)$

From equation (1), we will get:

$A=5400-B$

Substitute this value in equation (2):

$0.10(5400-B)+0.06B=444$

$540-0.10B+0.06B=444$

$540-0.04B=444$

$540-540-0.04B=444-540$

$-0.04B=-96$

$\frac{-0.04B}{-0.04}=\frac{-96}{-0.04}$

$A=2400$

Therefore, Maria should invest $2400 in A-rated bond.

Substitute $A=2400$ in equation (1):

$2400+B=5400$

$2400-2400+B=5400-2400$

$B=3,000$

Therefore, Maria should invest $3000 in B-rated bond.

6 0

3 years ago