The width used for the car spaces are taken as a multiples of the width of
the compact car spaces.
Correct response:
- The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>
Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.
We have;
Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)
New space design = 16·x + 9×(a·x) = x·(16 + 9·a)
When the dimensions of the initial and new arrangement are equal, we have;
10 + 12·a = 16 + 9·a
12·a - 9·a = 16 - 10 = 6
3·a = 6
a = 6 ÷ 3 = 2
a = 2
Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;
10 + 12·a < 16 + 9·a
Which gives;
x·(10 + 12·a) < x·(16 + 9·a)
Therefore;
The initial total car park space is less than the space required for 16
compact spaces and 9 full size spaces, therefore; the store owners are
incorrect.
Learn more about writing expressions here:
brainly.com/question/551090
B is the answer, because the half of the balls added
Known :
r = 6
h = 8
Asked :
V = ...?
Answer :
V = ⅓πr²h
= ⅓ × 3.14 × 6² × 8
= ⅓ × 3.14 × 36 × 8
= 3.14 × 12 × 8
= 301.44 units²
= <u>3</u><u>0</u><u>0</u><u> </u><u>units²</u> (rounded)
So, the volume of the cone is 300 units²
<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>
This is an exponential function.
If x = 0, 2^x = 2^0 = 1. The beginning value of 2^x is 1 and the beginning value of 51*2^x is 51.
Make a table and graph the points:
x y=51*2^x point (x,y)
-- --------------- ---------------
0 51 (0,51)
2 51*2^2 = 51(4) = 204 (2,204) and so on.
The graph shows up in both Quadrants I and II. Its y-intercept is (0,51). Its slope is always positive.
Answer:(_＼ヽ
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Step-by-step explanation: Theirs your help!
