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NeTakaya
3 years ago
6

Pls help me you guys are brilliant

Mathematics
1 answer:
IrinaVladis [17]3 years ago
6 0
He should buy the 24 pack
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One question. 100 Points. Need now.
Pie

Answer:

-4 < x ≤ 9

Step-by-step explanation:

8 0
3 years ago
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Label and connect the coordinates above
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You should add the picture so we can see
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3 years ago
CHECK YOUR KNOWLEDGE
PIT_PIT [208]
1. A rent paid
2. B 10
5 0
3 years ago
Evaluate the function fx = 4 * 7^t for x= -1 and x=2
Alex73 [517]
Well what i think you're asking here...I apologie if I'm wrong but what I did was 

f(-1) = 4 * 7^t = 4/7 

and 

f(2) = 4 * 7^t = 196.

Is this what you wanted if not I can...try another way. 
6 0
3 years ago
A park has a 3m tall tetherball pole, and a 6.8m tall flagpole. The lengths of their shadows are proportional to their heights.
vlada-n [284]

Complete question is;

A park has a 3 meter tall tether ball pole and a 6.8 m tall flagpole. The lengths of their shadows are proportional to their heights.

Which of the following could be the lengths of the shadows?

Choose 2 answers from the options attached.

Answer:

Options B & D

Step-by-step explanation:

From the question, the proportional relationship between the height and shadow length is a direct proportionality. This means that an increase in the height, leads to an increase in the length of shadow and vice versa. Thus, the height to shadow length ratio is a constant.

Now, if we use x and y to denote length of shadow of tether ball pole and length of flagpole receptively, we will have;

3/x = 6.8/y

Let's make y the subject.

y = 6.8x/3

Looking at the options;

Option A: When x = 1.35 m, we have;

y = (6.8 × 1.35)/3 = 3.06 m

For Option B:

When x = 1.8 m,

y= (6.8 × 1.8)/3 = 4.08 m

For Option C:

When x= 3.75 m,

y = (6.8 × 3.75)/3 = 8.5 m

For option D:

When x = 0.6

y = (6.8 × 0.6)/3 = 1.36 m

For option E;

When x = 2,

y = (6.8 × 2)/3 = 4.533 m

From our calculations, the only values of y that correspond with the given value of y in the options are Options B & D

5 0
3 years ago
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