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Lostsunrise [7]
3 years ago
12

Functions A,B and C are linear functions. Some values of function A are shown in the table. Function B has y-intercept of (3,0)

and a x-intercept of (5,0). Function C is defined by the equation y=3x+1.
HERES THE TABLE
X. 3,5,6
Y. 3,7,9​
Mathematics
1 answer:
earnstyle [38]3 years ago
3 0
You are not functioning right it’s a
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1<br> Select all of the true statements about the two triangles shown below.
Gekata [30.6K]

Answer:

Options B, C, D, F are correct answers

Step-by-step explanation:

Hope it helps you in your learning process.

4 0
3 years ago
Once Isabel rented the warehouse space, she decided to post ads on several social media sites to advertise her online bookstore.
Reika [66]
1. Number of books that were sold after 8 months:
f(8)=1000 \sqrt[3]{8}+1000&#10;f(8)=1000 * 2 + 100 = 2000+1000=3000
Answer: 3000 books
2. Graph of the function is in attachment.
Download docx
4 0
3 years ago
What two numbers add up to 6 and multiply to 12?
GuDViN [60]
Erm

x+y=6
xy=12


x+y=6
y=6-x
sub back

xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}

for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i

x= \frac{-(-6)+/- \sqrt{(-6)^2-4(1)(12)} }{2(1)}
x= \frac{6+/- \sqrt{36-48} }{2}
x= \frac{6+/- \sqrt{-12} }{2}
x= \frac{6+/- (\sqrt{-1})(\sqrt{12}) }{2}
x= \frac{6+/- (i)(2\sqrt{3}) }{2}
x= \frac{6+/- 2i\sqrt{3} }{2}
x=3+/-i√3

the numbers are 3+i√3 and 3-i√3
no real numbers tho
7 0
3 years ago
12.Divide. (x^2+2x+1/x^2-8x+16)/(x+1/x^2-16
lina2011 [118]
For this case we have the following expression:
 (x ^ 2 + 2x + 1 / x ^ 2-8x + 16) / (x + 1 / x ^ 2-16)
 Rewriting we have:
 (((x + 1) (x + 1)) / ((x-4) (x-4))) / (x + 1 / ((x + 4) (x-4)))
 Then, we cancel similar terms:
 ((x + 1) / (x-4)) / (1 / (x + 4))
 Rewriting:
 ((x + 1) (x + 4)) / (x-4)
 Answer:
 
((x + 1) (x + 4)) / (x-4)
3 0
3 years ago
Help help help help help help
MatroZZZ [7]

Answer:

221

Step-by-step explanation:

please mark me as brainlest

7 0
3 years ago
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