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Lostsunrise [7]
3 years ago
12

Functions A,B and C are linear functions. Some values of function A are shown in the table. Function B has y-intercept of (3,0)

and a x-intercept of (5,0). Function C is defined by the equation y=3x+1.
HERES THE TABLE
X. 3,5,6
Y. 3,7,9​
Mathematics
1 answer:
earnstyle [38]3 years ago
3 0
You are not functioning right it’s a
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Can someone help me?
mestny [16]

Answer:

Step-by-step explanation:

To do this, we must use the unit circle. At the angle \frac{\pi }{6} the coordinate pair is (\frac{\sqrt{3} }{2}, \frac{1}{2}) and the hypotenuse is 1

Now that we know these we can start using the trig functions

sin = y

cos = x

tan = \frac{y}{x}

And the other functions would be the reciprocal of these

csc = \frac{1}{y}

sec = \frac{1}{x}

cot = \frac{x}{y}

This would mean that

sinx = \frac{1}{2}

cosx =\frac{\sqrt{3} }{2}

tanx =\frac{1}{\sqrt{3} } or \frac{\sqrt{3} }{3} if you're supposed to rationalize your denominators

cscx = 2

secx = \frac{2}{\sqrt{3} } or \frac{2\sqrt{3} }{3}

cot = \sqrt{3}

6 0
3 years ago
From net earnings of $740 per month, Ginger Elliott must spend $200 for her portion of the rent on an apartment she shares with
MrRissso [65]
To find the percent, we do:
200/740=0.27←Find it in decimal form
0.27×100=27%←Multiply using 100 to find the percentage.

3 0
3 years ago
(x^2y^3) = (xy^a)^b
Rainbow [258]

Answer:

C. \frac{3}{2}

Step-by-step explanation:

To find the value f b, we need to compare the exponents.

The given exponential equation is:

( {x}^{2}  {y}^{3} )^{3}  = ( {x}  {y}^{a} )^{b}

Recall and apply the following rule of exponents.

( {x}^{m}  )^{n}  = {x}^{mn}

We apply this rule on both sides to get:

{x}^{2 \times 3}  {y}^{3 \times 3} =   {x}^{b}  {y}^{ab}

Simplify the exponents on the left.

{x}^{6}  {y}^{9} =   {x}^{b}  {y}^{ab}

Comparing exponents of the same variables on both sides,

b = 6 \: and \:\: ab = 9

\implies \: 6b = 9

Divide both sides by 6.

b =  \frac{9}{6}

b =  \frac{3}{2}

4 0
3 years ago
I’m literally struggling like can someone hel me plz this is due tomorrow
KonstantinChe [14]

Check the picture below.

4 0
3 years ago
Find the length and width of a rectangle that has the given perimeter and a maximum area. perimeter: 244 meters
MissTica
We know that

[perimeter of rectangle]=2*(<span>length+width)
</span>
Let
x-----------> length
y-----------> width
so
P=2*(x+y)-----------> 244=2*(x+y)-----> x+y=122-------> y=122-x

Area=x*y-------> x*(122-x)----> 122x-x²

find the derivative function and equals to zero

122-2x=0-----> 122=2x----------> x=61 m
y=122-x------> y=122-61---------> y=61 m

<span>the maximum area is given by a square
</span>
the answer is
is a square of side 61 m


6 0
3 years ago
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