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snow_lady [41]
3 years ago
7

What is the solution to the inequality −2 x −98 x < −98

Mathematics
1 answer:
Yuliya22 [10]3 years ago
8 0
Use the app (Socratic) and just take a picture of that question and it will give you the answer
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What is the greatest common factor of 16 and 48?​
Anna11 [10]

Answer:

16

Step-by-step explanation:

We can list out each of the numbers' prime factors first before deciding their greatest common factor.

16: 2 × 2 × 2 × 2

48: 2 × 2 × 2 × 2 × 3

As you can see the bolded parts, these are the common factors of the two numbers. To find the greatest common factors, we just have to multiply all their common factors together.  

Greatest common factor of 16 & 48: 2 × 2 × 2 × 2 = 16

7 0
3 years ago
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From the following figure, find the value of ∠AOC and ∠BOC?
g100num [7]

Step-by-step explanation:

paki ayos (*ˊᗜˋ*)ᵗᑋᵃᐢᵏ ᵞᵒᵘ sa pts

8 0
3 years ago
Help fast please....
IrinaVladis [17]
The second one is the answer
7 0
2 years ago
Yesterday noah ran 2 1/2 miles in 3/5 hour. Emily ran 3 3/4 miles in 5/6 hour. Anna ran 3 1/2 miles in 3/4 hour how fast in mile
Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

To calculate the speed of each one we proceed as follows:

speed=distance/time

a] Noah's speed:

distance=2.5 miles

time=3/5 hours

speed=(2 1/2)/(3/5)

=(5/2)/(3/5)

=5/2×5/3

=25/6

=4 1/6 mi/hr

Emily's speed

distance=3 3/4 miles

time=5/6 hour

thus

speed=(3 3/4)/(5/6)

=15/4)/(5/6)

=15/4×6/5

=4 1/2 mi/hr

Anna's speed:

distance=3 1/3 miles

time=3/5

speed=(3 1/3)/(3/5

=(10/3)/(3/5)

=10/3×5/3

=5 5/9 mi/hr

Anna was the fastest

6 0
3 years ago
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the median of the values in a data set is y. if 48 were subtracted from each of the values in the data set what would be the med
Nataliya [291]

 Answer: Y-48

<span>If the median of the values in the data set is Y, it means that Y is the value in the middle of the data set. If 48 will be deducted from each of all values in the data set including Y, then the median of the resulting value will be Y-48. </span>

3 0
3 years ago
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