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4 years ago

What is the answer to this question? Please help!

Mathematics

2 answers:

maks197457 [2]4 years ago

6 0

Answer:

Step-by-step explanation:

$-3\sqrt{2}+3\sqrt{8}= \\\\-3\sqrt{2}+3\sqrt{2\cdot 2^2}= \\\\-3\sqrt{2}+6\sqrt{2}= \\\\3\sqrt{2}$

Hope this helps!

mario62 [17]4 years ago

5 0

3 square root of 2 is the answer

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Solve for x: |3x + 12| = 18

Alla [95]

Answer:

X = 2 or X = -10

Step-by-step explanation:

We know either3x+12=18or3x+12=−18

3x+12=18(Possibility 1)

3x+12−12=18−12(Subtract 12 from both sides)

3x=6

(Divide both sides by 3)

x=2

3x+12=−18(Possibility 2)

3x+12−12=−18−12(Subtract 12 from both sides)

3x=−30

−30

(Divide both sides by 3)

x=−10

Answer:

x=2 or x=−10

4 0

3 years ago

P is directly proportional to the cube of q

Molodets [167]

Answer:

p=q^3

Step-by-step explanation:

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3 years ago

(-9)-(-13)+(3)<img src="https://tex.z-dn.net/?f=" id="TexFormula1" title="" alt="" align="absmiddle" class="latex-formula">

Cloud [144]

Hi,

$( - 9) - ( - 13) + (3) \\ - 9 - ( - 13) + (3) \\ - 9 + 13 + 3 = 7$

Hope this helps.
r3t40

4 0

3 years ago

What is the factorization of the trinomial below?x3 - 12x2 + 35x?

Fed [463]

X³ - 12x² + 35x

x(x² - 12x + 35)

x(x-5)(x-7)

4 0

3 years ago

Read 2 more answers

Describe lengths of three segments that could not be used to form a triangle. Segments with lengths of 5 in., 5 in., and ______

Vesna [10]

Answer:

$c = 11$

Step-by-step explanation:

Given

Let the three sides be a, b and c

Such that:

$a = b= 5$

Required

Find c such that a, b and c do not form a triangle

To do this, we make use of the following triangle inequality theorem

$a + b > c$

$a + c > b$

$b + c > a$

To get a valid triangle, the above inequalities must be true.

To get an invalid triangle, at least one must not be true.

Substitute: $a = b= 5$

$5 + 5 > c$ $===>$ $10 > c$

$5 + c > 5$ $===>$ $c > 5 - 5$ $===>$ $c > 0$

The results of the inequality is: $10 > c$ and $c > 0$

Rewrite as: $c > 0$ and $c < 10$

$0 < c < 10$

This means that, the values of c that make a valid triangle are 1 to 9 (inclusive)

Any value outside this range, cannot form a triangle

So, we can say:

$c = 11$ , since no options are given

8 0

3 years ago