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4vir4ik [10]
2 years ago
12

I need help plz help me

Mathematics
2 answers:
Tomtit [17]2 years ago
8 0
5 pounds = $40

1 pound = $8

8 pounds = $64
slega [8]2 years ago
3 0
64 is the answer because it’s 8 for one And 8*8=64
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The drama department needs to raise at least 575.00 for a trip to see a play they have already 163.00 if they sell candybars for
olga2289 [7]

Answer:

330

Step-by-step explanation:

575 - 163 = 412

412 / 1.25 = 329.6

Since we need to exceed the goal and we can only sell whole candy bars, we round 329.6 up to 330.

3 0
3 years ago
The sum of 3 times a number and 4 is 9.
larisa [96]

Answer: x = 5/3

Step-by-step explanation:

Let the number be x

Then

3x + 4 = 9

3x = 9-4

3x = 5

x = 5/3

please click thanks and mark brainliest if you like :)

8 0
3 years ago
Read 2 more answers
Which are the solutions of x^2 = –11x + 4?
strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

x^2 + 11x - 4 = 0

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}

where x_{1,2} is a compact way to indicate both solutions x_1 and x_2, while a,b,c are the coefficients of the quadratic equation, i.e. we consider the polynomial ax^2+bx+c.

So, in your case, we have a=1,\ \ b=11,\ \ c=-4

Plug those values into the formula to get

x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}

So, the two solutions are

x_1 = \frac{-11+\sqrt{137}}{2}

x_2 = \frac{-11-\sqrt{137}}{2}

3 0
3 years ago
Someone pls help! <br> write the expression in radical form. 2 4/5
kipiarov [429]

Answer:

  \sqrt[5]{2^4}

Step-by-step explanation:

Maybe you want 2^(4/5) in radical form.

The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.

  2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}

__

In many cases, it is preferred to keep the power inside the radical symbol.

7 0
3 years ago
Hello pls help I'm dumb thx it's pre calc
Bumek [7]
(f-g)(x)=f(x)-g(x)=
\frac{2x+6}{3x}-\frac{\sqrt{x}-8}{3x}=
\frac{2x+6-(\sqrt{x}-8)}{3x}=
\frac{2x+6-\sqrt{x}+8}{3x}=
\frac{2x-\sqrt{x}+14}{3x}
answer is A
3 0
3 years ago
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