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Shalnov [3]
3 years ago
15

Tollowing: a) 3x + 4 = 9.5 7 + 2x = b) = 5

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

See attachment for math work and answer.

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Evaluate the surface integral. s x ds, s is the triangular region with vertices (1, 0, 0), (0, −2, 0), and (0, 0, 12).
aniked [119]
Parameterize the surface by

\mathbf r(s,t)=(1-s)(0,0,12)+s\bigg((1-t)(1,0,0)+t(0,-2,0)\bigg)
\implies\mathbf r(s,t)=(x(s,t),y(s,t),z(s,t))=(s-st,-2st,12-12s)

where (s,t)\in(0,1)\times(0,1). We have

\|\mathbf r_s\times\mathbf r_t\|=\|(1-t,-2t,-12)\times(-s,-2s,0)\|=2\sqrt{181}s

The surface integral is then

\displaystyle\iint_Sx\,\mathrm dS=2\sqrt{181}\int_{s=0}^{s=1}\int_{t=0}^{t=1}s(s-st)\,\mathrm dt\,\mathrm ds
=\displaystyle2\sqrt{181}\left(\int_{s=0}^{s=1}s^2\,\mathrm ds\right)\left(\int_{t=0}^{t=1}(1-t)\,\mathrm dt\right)
=\dfrac{\sqrt{181}}3
7 0
3 years ago
5÷20<br> I need help<br> I Just need the answer
bija089 [108]

Answer:

0.25

Step-by-step explanation:

8 0
3 years ago
A fitness club has two options, one for members and one for nonmembers. Members pay a one-time registration fee of $12 plus $8 p
Liula [17]

Answer:

See below.

Step-by-step explanation:

Let's look at the cost for members (C1) first.  Let x be the number of visits.

C1(x) = 12 + 8x

For non-members (C2), we can do the same.

C2(x) = 10x

You can graph these two equations.

x        C1         C2

0       12          0

1        20        10

2       28        20

3       36        30

4       44        40

5       52        50

6       60        60

7       68        70

Let's make the two equations equal, to find out where the benefit is the same.

12 + 8x = 10x

2x = 12

x = 6

Up to 5 visits, the non-member cost is better.  At 6 visits, there's the same price.  For more than 6 visits, the member cost is better.

7 0
3 years ago
Pleas y'all help me with this
Fynjy0 [20]

Answer:

-\frac{26}{2}/  -\sqrt{9}/  13.5(percent)/ 0/ 13.5

Step-by-step explanation:

3 0
3 years ago
Complete the comparison: 26 &lt;
EastWind [94]
26< any number larger than 26 (whole numbers and fractions/decimals)
6 0
3 years ago
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