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Cerrena [4.2K]
3 years ago
10

DONT REALLY NEED ANY HELP OR ANYTHING PLZ DONT ANSWER WILL NOT GIVE BRAINLIEST

Mathematics
1 answer:
musickatia [10]3 years ago
7 0

Answer:

Hi

Step-by-step explanation:

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Pls help, and explain. Will give brainliest
malfutka [58]

Cost of 12 notebooks = $9

Ratio of number of notebooks to its price

= 12:9

= 4:3 <em>(because we reduced it to the simplest form by dividing both numerator and denominator by 3)</em>

Let the cost of 8 notebooks be x.

Then, 8:x = 4:3

=> 8/x = 4/3

=> (8×3)/4 = x

=> 24/4 = x

=> 6 = x

So, the cost of 8 notebooks is $6.

8 0
3 years ago
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I need help with 10. I NEED HELP ASAP
tester [92]
The answer is A. You have to use pathagoream theorem
8 0
4 years ago
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Maya had $27. She spent all the money on buying 3 burgers for $x each and 2 sandwiches for $y each. If Maya had bought 2 burgers
Maru [420]
<span>3x + 2 y = 27 
2 x + y = 27-11 = 16 
================= 

The student's conclusion is correct because the solution to the system of equations 3x + 2y = 27 and 2x + y = 16 is (5, 6). C
</span>
8 0
4 years ago
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Which number is irrational?<br> A. square root of 5<br> B. 0.777...<br> C. 0.454545...<br> D. 0.3
Veronika [31]

Answer:

A

Step-by-step explanation:

The square root of 5 is irrational because it cannot be expressed as a fraction.

Meanwhile, all 3 other answer choices are not irrational because they can be put into fraction form.

7 0
3 years ago
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PLEASE HELP!
kotykmax [81]
First off, you can rewrite your equation like so: c=(a-b)x. You can then plug in your given constraints for your choices. If a-b = 1 and c = 0 leaving: 0=1(x), x must equal 0 and only 0 as any constant multiplied by 0 equals 0. So that choice is eliminated. Now let's consider when a=b and c != 0. Since we are given a-b and a=b and c != 0, we have:
c = 0x. This contradicts our claim we made about our constraints. C cannot equal zero but we have a-b=0. Therefore, this claim makes no sense as any value for x will not satisfy the equation. This choice is valid. When a=b and c=0, we have: 0 = 0x. Here, x can be any value and still return 0 as an answer. This choice is valid. If a-b=1 and c != 1, we have: c = 1x. Our only rule here is that c cannot equal 1. This means that x can be any value other than 1 so this choice can be marked down. If a != b and c=0, this gives: 0 = (a-b)x. Given that a-b can be any value, x must be equal to only 0 to satisfy this equation so this choice can't be correct. So the right answers are: option 2, option 3, option 4 and option 5.
6 0
3 years ago
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