Answer:
the last one
Step-by-step explanation:
In the last one, it takes all of the numbers in the one parentheses and distributes it to the 0.5.
Look at the picture. (sorry for the messy writing)
<u>Answer: </u>Taking a Photo of another photo displayed in an art gallery and claiming it as your own
<u>Step-by-step explanation:</u><u> </u>Because you are claiming something as your own(when it's not) is considered plagiarism and no other situation is considered plagiarism but this one so really the <u><em>process of elimination</em></u> explains the answer to this question
Step-by-step explanation:
The point-slope form of an equation of a line:

m - slope
(x₁, y₁) - given point

An integer may be a multiple of 3.
An integer may be 1 greater than a multiple of 3.
An integer may be 2 greater than a multiple of 3.
It is redundant to say an integer is 3 greater than a multiple of 3 (that's just a multiple of 3, we've got it covered). Same for 4, 5, 6, 7...
Let's consider a number which is a multiple of 3. Clearly, we can write 3+3+3+3+... until we reach the number. It can be written as only 3's.
Let's consider a number which is 2 greater than a multiple of 3. If we subtract 5 from that number, it'll be a multiple of 3. That means we can write the number as 5+3+3+3+3+... Of course, the number must be at least 8.
Let's consider a number which is 1 greater than a multiple of 3. If we subtract 5 from that number, it'll be 2 greater than a multiple of 3. If we subtract another 5, it'll be a multiple of 3. That means we can write the number as 5+5+3+3+3+3+... Of course, the number must be at least 13.
That's it. We considered all the numbers. We forgot 9, 10, 11, and 12, but these are easy peasy.
Beautiful question.
Yes, the rules of scientific notation are:
1. All non-zero digits are significant
2. Zeros in between non-zeros are significant.
3. Zeros to the left of the first non-zero number are NOT significant.
4. Zeros to the right of non-zero numbers are significant IF a decimal point is present.
P.S: if you need help with sig fig rounding, let me know.