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3 years ago

9

Ben drinks tea at an incredible rate.He drinks 3 1/2 liters of tea every 2/3 of an hour.Ben drinks tea at a constant rate. How m

any liters of tea does he drink in one hour

1 answer:

Yuri [45]3 years ago

4 0

Ben drinks 5 1/4 liters. Just multiply 3 1/2 times 1.5

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Logan genetically engineered a new type of fir tree and a new type of pine tree. The combined height of one fir tree and one pin

Serjik [45]

I'm so sorry I wish I knew the answer to your question

4 0

3 years ago

Ruby’s homework covers multiplication with the powers of 10 the first question on her homework is 82.6 x 10 to the power of 2 wh

Elina [12.6K]

Answer:

826

Step-by-step explanation:

82.6 x 10 to the power of 2 :

8.26 * 10^2

8.26 * (10 * 10)

8.26 * (100)

= 826

7 0

3 years ago

(b) The area of a rectangular pool is 5488 m\2 If the length of the pool is 98 m, what is its width?

mrs_skeptik [129]

Answer:

56

Step-by-step explanation:

To find the area of a rectangle we have the foruma A=WxL.

But we already have the area and length so we can plug that in

5488=Wx98

Now its an algebreic expression.

SInce its multiplying we do the opposite, so we divide 98 on both sides.

98/98 crosses itself out so now its 5488/98. Which equals 56. So now our expression is W=56. To fact check we put the numbers 56 and 98 into the formula to see if we get 5488.

A=56x98

A=5488

7 0

2 years ago

The following table shows the weights, in hundreds of pounds, for six selected cars. Also shown is the corresponding fuel eff

Reika [66]

Answer:

Step-by-step explanation:

Given is a table showing the weights, in hundreds of pounds, for six selected cars. Also shown is the corresponding fuel efficiency, in miles per gallon (mpg), for the car in city driving.

Weight Fuel eff. x^2 xy y^2

X Y

28 20 784 560 400

3 22 9 66 484

35 19 1225 665 361

32 22 1024 704 484

30 23 900 690 529

29 21 841 609 441

Mean 26.16666667 21.16666667 797.1666667 549 449.8333333

Variance 112.4722222 1.805555556

Covariance -553.8611111

r -0.341120235

Correlaton coefficient =cov (xy)/S_x S_y

Covariance (x,y) = E(xy)-E(x)E(y)

The correlation coefficient between the weight of a car and the fuel efficiency is -0.341

8 0

3 years ago

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

4 years ago