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Lena [83]
3 years ago
11

Identify the x and y intercepts from the give equation: 5x – 2y = 10

Mathematics
1 answer:
Iteru [2.4K]3 years ago
3 0

Answer:

x-intercept : (2, 0)

y-intercept : (0, -5)

Step-by-step explanation:

The x-intercept is where y = 0, and the y-intercept is where x = 0. To find the intercepts, substitute a zero in for the other variable, and solve.

So the x-intercept of 5x – 2y = 10 is

5x – 2y = 10 → 5x – 2(0) = 10 → 5x = 10 →

x = 2 → (2, 0).

So the y-intercept of 5x – 2y = 10 is

5x – 2y = 10 → 5(0) – 2y = 10 → -2y = 10 →

y = -5 → (0, -5).

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Please do this math for me or else i will steal your cookies
kompoz [17]

Answer:

Step-by-step explanation:

1.

-7x+16=58\\\\\mathrm{Subtract\:}16\mathrm{\:from\:both\:sides}\\-7x+16-16=58-16\\\\-7x=42\\\\\mathrm{Divide\:both\:sides\:by\:}-7\\\\\frac{-7x}{-7}=\frac{42}{-7}\\\\x =-6

2.

-2x+15=-9\\\\\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}\\\\-2x+15-15=-9-15\\\\-2x=-24\\\\\mathrm{Divide\:both\:sides\:by\:}-2\\\\\frac{-2x}{-2}=\frac{-24}{-2}\\\\x=12\\

3.

5x-4=36\\\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\\\5x-4+4=36+4\\\\5x=40\\\\\mathrm{Divide\:both\:sides\:by\:}5\\\\\frac{5x}{5}=\frac{40}{5}\\\\x=8

4.

25-3x=88\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\\\25-3x-25=88-25\\\\\mathrm{Divide\:both\:sides\:by\:}-3\\\\\frac{-3x}{-3}=\frac{63}{-3}\\\\x=-21

5.

-11=7-x\\\\\mathrm{Add\:}x\mathrm{\:to\:both\:sides}\\\\-11+x=7-x+x\\\\-11+x=7\\\\\mathrm{Add\:}11\mathrm{\:to\:both\:sides}\\\\-11+x+11=7+11\\\\x=18

6.

65+15x=35\\\\\mathrm{Subtract\:}65\mathrm{\:from\:both\:sides}\\\\65+15x-65=35-65\\\\\mathrm{Divide\:both\:sides\:by\:}15\\\\\frac{15x}{15}=\frac{-30}{15}\\\\x=-2

7.

\frac{1}{2} x-18=2\\\\\mathrm{Add\:}18\mathrm{\:to\:both\:sides}\\\\\frac{1}{2}x-18+18=2+18\\\\\frac{1}{2}x=20\\\\\mathrm{Multiply\:both\:sides\:by\:}2\\\\2\times\frac{1}{2}x=20\times \:2\\\\x=4

8.

\frac{2}{3}x-10=-12 \\\\\mathrm{Add\:}10\mathrm{\:to\:both\:sides}\\\\\frac{2}{3}x-10+10=-12+10\\\\\frac{2}{3}x=-2\\\\Divide\:both\:sides\:by\: 2/3\\\\\frac{2}{3}x\div \frac{2}{3}  =-2\div \frac{2}{3}  \\\\\frac{2}{3}  x\times \frac{3}{2} =-2\times\frac{3}{2} \\\\x =-3

9.

6-\frac{1}{3}x=-1 \\\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\\\6-\frac{1}{3}x-6=-1-6\\\\-\frac{1}{3}x=-7\\\\\mathrm{Multiply\:both\:sides\:by\:}-3\\\\\left(-\frac{1}{3}x\right)\left(-3\right)=\left(-7\right)\left(-3\right)\\\\x=21

10.

4-9x=-14\\\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\\\4-9x-4=-14-4\\\\-9x=-18\\\\\mathrm{Divide\:both\:sides\:by\:}-9\\\\\frac{-9x}{-9}=\frac{-18}{-9}\\\\x=2

11.

11-x=29\\\\\mathrm{Subtract\:}11\mathrm{\:from\:both\:sides}\\\\-x=18\\\\\mathrm{Divide\:both\:sides\:by\:}-1\\\\\frac{-x}{-1}=\frac{18}{-1}\\\\x=-18

12.

-9-11x=68\\\\\mathrm{Add\:}9\mathrm{\:to\:both\:sides}\\\\-9-11x+9=68+9\\\\-11x=77\\\\\mathrm{Divide\:both\:sides\:by\:}-11\\\\\frac{-11x}{-11}=\frac{77}{-11}\\\\x=-7

13.

45+\frac{5}{6}x =50\\\\\mathrm{Subtract\:}45\mathrm{\:from\:both\:sides}\\\\45+\frac{5}{6}x-45=50-45\\\\\frac{5}{6}x=5\\\\\mathrm{Divide\:both\:sides\:by\:}5/6\\\\\frac{5}{6} x\div\frac{5}{6}=5\div\frac{5}{6}\\\\\frac{5}{6}x\times \frac{6}{5}= 5\times\frac{6}{5}\\\\ x=6

14.

-5x+17=-33\\\\\mathrm{Subtract\:}17\mathrm{\:from\:both\:sides}\\\\-5x+17-17=-33-17\\\\\mathrm{Divide\:both\:sides\:by\:}-5\\\\\frac{-5x}{-5}=\frac{-50}{-5}\\\\x=10

15.

95=-4+33x\\\\-4+33x=95\\\\\mathrm{Add\:}4\mathrm{\:to\:both\:sides}\\\\-4+33x+4=95+4\\\\\mathrm{Divide\:both\:sides\:by\:}33\\\\\frac{33x}{33}=\frac{99}{33}\\\\x=3

3 0
3 years ago
How do i solve for y and z?
MAVERICK [17]
Y = 6, z = 2

~Hope this helped!~

(The first page is the beginning of the equation, and the next page is the ending)

5 0
4 years ago
Not sure how to do this
OLEGan [10]
It's pretty simple! So it looks like you are learning proportions. You would cross multiply to achieve your answer. 

First, let's do your first problem: 

2     12
--- = ----
5       n 

You would take 5 and multiply it by 12 and get 60! Then you would do the same with 2 times n, giving you 2n (because you do not know what n represents YET.) 

Now you should have this:
60=2n OR 2n=60

We must isolate our variable, in order to do that, get rid of two! But how? You would do this by dividing 2n by 2. Yet in equations, when you do something to one side, you must do it to the other because they must be EQUAL! (hence the "equa-" in equation) 

2n=60
---   ---
2      2  DIVIDE 2 into 60
----------
n= 30   Simplify! 

Your final answer for the first question is n= 30! 



8 0
3 years ago
A student ran out of time on a multiple choice exam and randomly guessed the answers for 2 problems. Each problem had 5 answer c
frozen [14]
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i hope this helps!!
3 0
3 years ago
Solve for x.
Aliun [14]

9514 1404 393

Answer:

  x = 3.6

Step-by-step explanation:

The angle bisector divides the segments proportionally. This means they satisfy ...

  bottom segment / side segment = x/6 = (6-x)/4

Multiplying by 12 gives ...

  2x = 3(6 -x)

  2x = 18 -3x . . . . . eliminate parentheses

  5x = 18 . . . . . . . . add 3x

  x = 3.6 . . . . . . . . . divide by 5

_____

<em>Alternate solution</em>

I like to try to work these mentally. The total of side lengths is 10, so the total base length (6) is 6/10 = 0.6 times that. Then x will be 0.6 times the left side length: 0.6·6 = 3.6 = x.

8 0
3 years ago
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