If m/2 = 3x +1 and m/3= 2x +4, what is mZ2? 17 52. 90 38

Hey is there any chance anyone could help me with this question ASAP?? Tysm :)

Elden [556K]

Answer:

6

Step-by-step explanation:

A = π. r²

36π = π. r²

eliminate π, we get:

36=r²

r=√36

r = 6

4 0

3 years ago

Read 2 more answers

Jonah drives from his car to and from work. The total length of the trip to and from work is 19.2 miles. In August, Jonah worked

natita [175]

ANSWER

The total length of the trip to and from work in August is

$403.2 \: miles$

EXPLANATION

The total length of the trip to and from work is

$19.2 \: miles$

If Jonah worked 21 days in August,

Then, the total length of the trip to and from work is
$= 21 \times 19.2 \: miles$

Change the decimal to fraction and multiply,

$= 21 \times \frac{192}{10} miles$

$= \frac{21 \times 192}{10}$

$= \frac{4032}{10} miles$

Convert back to decimal

$= 403.2 \: miles$

6 0

3 years ago

How do I do this problem?

anyanavicka [17]

That's D. n² ÷ 5 because it says the division of n squared and 5.

7 0

3 years ago

Write the integer that represents the opposite of each situation 100 feet above sea level

Sveta_85 [38]

The answer is 100 m below sea level

6 0

3 years ago

In a study on the time that

krok68 [10]

The 95% confidence interval of the population mean, in years, is (4.3, 5.3). 4 years is not part of the confidence interval, which means that it contradicts the fact that 39% of students get their college degree in four years.

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To solve this question, we need to find the confidence interval for the amount of time it takes the students to get the degree.

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

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The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 80 - 1 = 79

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95% confidence interval

Standard level of confidence, we have to find a value of T, which is found looking at the t table, with 79 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 1.9905.

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The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.9905\frac{2.2}{\sqrt{80}} = 0.5$

In which s is the standard deviation of the sample and n is the size of the sample.

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The lower end of the interval is the sample mean subtracted by M. So it is 4.8 - 0.3 = 4.3 years.

The upper end of the interval is the sample mean added to M. So it is 4.8 + 0.3 = 5.3 years.

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The 95% confidence interval of the population mean, in years, is (4.3, 5.3). 4 years is not part of the confidence interval, which means that it contradicts the fact that 39% of students get their college degree in four years.

A similar question is given at brainly.com/question/24278748

6 0

3 years ago