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LiRa [457]
3 years ago
11

You have $20 to spend on taxi fare. The ride costs $5 plus $2.50 per mile. Write an inequality to determine how many miles you c

an ride for $20.
Mathematics
1 answer:
BARSIC [14]3 years ago
4 0

Answer: Maximum 6 miles

Step-by-step explanation: In total you have $20.

Base fare of taxi is $5.

Per mile cost is $2.50.

Your total cost is  where x is the number of miles. Since you're on a budget of maximum $20, the cost should be less than or equal to $20. We can write:

To find how many miles we can write, let's solve the inequality:

.

This means 6 is the maximum number of miles you can ride with $20.

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Kayla is on level 12 of a new game. Everyday she completes 6 new levels. Maddy is on level 28 of the same game. Everyday she com
ankoles [38]

Answer:

Kayla and Maddy will be in the same level in 4 days.

Step-by-step explanation:

Kayla: y = 6x + 12

Maddy: y = 2x  + 28

6x + 12 = 2x + 28

Subtract 2x from both sides;

4x + 12 = 28

Subtract 12 from both sides;

4x = 16

Divide both sides by 4;

x = 4

3 0
3 years ago
Read 2 more answers
Find vertical and horizontal asymtope for (x^2+2x-48)/x+8
bonufazy [111]
There are none.

y=\dfrac{x^{2}+2x-48}{x+8}=\dfrac{(x+8)(x-6)}{x+8}\\\\y=x-6

The expression describes a straight line with a hole at x=-8 where it is undefined.

5 0
3 years ago
~(25 Points)~
murzikaleks [220]
The answer is the third one
3 0
4 years ago
How many positive integers less than 250 are multiples of 5, but not multiples of 10?
SashulF [63]

Answer:

Step-by-step explanations: sometimes 5 times (number) is 250 but in this case your teacher did not tell you to multiply it by 10 but instead multiplying it by 5

8 0
4 years ago
Read 2 more answers
Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon
Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

h(t)=-16t^2+40t+5

we know that

When the ball hits the ground, the height is equal to zero

so

-16t^2+40t+5=0

The formula to solve a quadratic equation of the form

at^{2} +bt+c=0

is equal to

t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+40t+5=0

so

a=-16\\b=40\\c=5

substitute in the formula

t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}

t=\frac{-40\pm\sqrt{1,920}} {-32}

t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec

t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec

therefore

The solution  is t=2.62 seconds

4 0
3 years ago
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