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LiRa [457]
3 years ago
11

You have $20 to spend on taxi fare. The ride costs $5 plus $2.50 per mile. Write an inequality to determine how many miles you c

an ride for $20.
Mathematics
1 answer:
BARSIC [14]3 years ago
4 0

Answer: Maximum 6 miles

Step-by-step explanation: In total you have $20.

Base fare of taxi is $5.

Per mile cost is $2.50.

Your total cost is  where x is the number of miles. Since you're on a budget of maximum $20, the cost should be less than or equal to $20. We can write:

To find how many miles we can write, let's solve the inequality:

.

This means 6 is the maximum number of miles you can ride with $20.

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Simplify -6.8+ (-2.71)
vova2212 [387]

Answer:

4.09

Step-by-step explanation

since negatives over power positive numbers

-6.8+(-2.71) - will simplify plus into minus

-6.8 - 2.71 - now just subtract

6.8-2.71=4.09

5 0
2 years ago
What is 12 times 12 plus 1
sammy [17]

Answer:

145

Step-by-step explanation:

just use a calculator

3 0
3 years ago
Read 2 more answers
Mark all the statements that are true <br> a) the domain for this function is the set {3}
telo118 [61]

Answer:

the answer is 6 statements

Step-by-step explanation:

8 0
2 years ago
The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
What Val are restricted from the domain of
djverab [1.8K]

<u>Given</u>:

The given expression is \frac{\left(4 x^{2}-4 x+1\right)}{(2 x-1)^{2}}

We need to determine the values for which the domain is restricted.

<u>Restricted values:</u>

Let us determine the values restricted from the domain.

To determine the restricted values from the domain, let us set the denominator the function not equal to zero.

Thus, we have;

(2x-1)^2\neq 0

Taking square root on both sides, we get;

2x-1\neq 0

     2x\neq 1

      x\neq \frac{1}{2}

Thus, the restricted value from the domain is x\neq \frac{1}{2}

Hence, Option A is the correct answer.

7 0
3 years ago
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