Answer:
We will divide the 15 days in five periods of 3 consecutive days each.
Now to solve this we will use the pigeonhole principle.
This states that if (N+1) pigeons occupy N holes, then some hole must have at least 2 pigeons.
So, we have n=300 pigeons and k=5 holes.
Hence, there is a period of 3 consecutive days in which the website was hit at least 60 times.
Answer:
The probability that he ends up with a full house is 0.0083.
Step-by-step explanation:
We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.
We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).
We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);
Only in these two situations, he will end up with a full house.
Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.
So, the ways in which we can draw two kings from available three kings is given by = {∵ one king is already there}
= {∵
}
= = 0.0028
Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by =
=
= = 0.0055
Now, probability that he ends up with a full house =
= = <u>0.0083</u>.