Write as a product:<br> a2+b2–2ab

How many times can 95 go into 96

Tanzania [10]

Answer:24 times

Step-by-step explanation:Hi there!

First of all, division is the opposite of multiplication. So if I

divide 72 by 3 I should get 24, since 3*24 = 72.

(You might notice that our division looks sort of like the

multiplication:

24

X 3

___

12

60

----

72

just in a different order.)

OK, back to long division.

The process of long division goes sort of like this:

1. Write the problem

2. Make a guess of what the answer will be

3. Check your guess, fix it if you need to

4. "Bring down"

5. Repeat steps 2-4 until you're out of digits

So for 72 divided by three, the process would go like this:

1. Write the problem

----

3|72

That means 72 divided by 3, also called 3 into 72, etc.

2. Make a guess of what the answer is.

Let's cover up the 2 in 72 for a minute: (This lets us ignore the place

value, etc.)

----

3|7?

Now let's ask: How many times does 3 go into 7?

You can make whatever guess you want. But since we have a good idea of

what the answer should be, let's guess 2.

Now we write the 2 above the 7 like this:

2

----

3|7?

Now, to check that we're right, we need to subtract 2 3's from 7.

We do this by multiplying 2X3 (to get 6) and then writing:

2

----

3| 7?

-6

__

1

We need the 2 from 72 again, so let's write it in again. In fact, we're

going to "bring it down" next to the 1 to make 12. Then we'll guess how

many times 3 goes into 12, and so on.

Anyway:

2

----

3| 72

-6 | <---that's supposed to be an arrow reminding you that we're

__\ / bringing down the 2 to make 12

12

Ok. So, how many times does 3 go into 12? Let's guess 4 (sorry, I'm

cheating since I know the answer already!)

24

----

3| 72

-6

-

12

Now let's multiply 3 X 4. Wow! We get 12. If we subtract 12-12

24

----

3| 72

-6

-

12

- 12

---

0

Now, we can check to make sure that 3 X 24 really does equal 72, and

we're done.

4 0

3 years ago

WILL MARK BRAINLIEST!! Which of the following ordered pairs are y-intercepts? Check all that apply.

Y_Kistochka [10]

Y intercept is where the line meets the Y axis
So the points shd be in (0,y) form.

So (0,0) (0,-7) (0,-0.25) are the y-intercepts in the following.

8 0

3 years ago

Read 2 more answers

What's the factor of 18 and the sum of -9?

Klio2033 [76]

Factor:-6,-3
-6-3= -9

4 0

2 years ago

Read 2 more answers

A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In

lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

P.Q. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of males having blood disorder= $\frac{250}{1000}$ = 0.25

$\hat p_2$ = sample proportion of females having blood disorder = $\frac{275}{1000}$ = 0.275

$n_1$ = sample of males = 1000

$n_2$ = sample of females = 1000

$p_1$ = population proportion of males having blood disorder

$p_2$ = population proportion of females having blood disorder

<em>Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.</em>

<u>So, 95% confidence interval for the difference between the population proportions, </u><u>(</u> $p_1-p_2$ <u>)</u><u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ${(\hat p_1-\hat p_2)-(p_1-p_2)}$ < $1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

P( $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ( $p_1-p_2$ ) < $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

<u>95% confidence interval for</u> ( $p_1-p_2$ ) =

[ $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ , $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ]

= [ $(0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ , $(0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ ]

= [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0

3 years ago

Trapezia ABCD and PQRS are similar.<br> Find the area shaded in green.

avanturin [10]

The area shaded in green is 864 cm²

<h3>Similar figures</h3>

Similar figures, corresponding angles are congruent and the sides are ratio of each other. Therefore,

AB / PQ = CD / RS

30 / 10 = 24 / RS

30RS = 240

RS = 240 / 30

RS = 8 cm

let find the height of trapezium PQRS.

AB / PQ = 36 / h

30 / 10 = 36 / h

30h = 360

h = 360 / 30

h = 12 cm

Therefore,

area of the green portion = area of ABCD - area of PQRS

<h3>Area of a trapezium</h3>

area = 1 / 2(a + b)h

Therefore,

area of ABCD = 1 / 2(24 + 30)36 = 1 / 2 (54)36 = 1944 / 2 = 972 cm²

area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²

Area of the green portion = 972 - 108 = 864 cm²

learn more on trapezium here: brainly.com/question/11961445

6 0

2 years ago

Write as a product: a2+b2–2ab –25