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dsp73
3 years ago
11

Analyze the diagram below and complete the instructions

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Hope this helped! Please let me know if I'm wrong!

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Find the value of n<br><br><br><br><br>1) 15/40 =n/3​
stepladder [879]

Answer:

n = 1.125

Step-by-step explanation:

\frac{15}{40} = \frac{n}{3}

(Use Cross Product)

40n = 15 × 3

40n = 45

n = 1.125

7 0
3 years ago
Whats the mean,median,mode,range, of 6.5,7.5,7,8,8,8,9,10.5,10?
nekit [7.7K]
Mode=8
Range=4
Mean=15.2777778(rounded up to 15.28 or 15.3)
Median=8

7 0
3 years ago
When creating lines of best fit, do you believe that estimation by inspection of the equation is best or do you think it should
Alex73 [517]

Answer:

Estimation by inspection is better than trying to determine the line of best fit exactly

i) For a scatter plot : The use of estimation by inspection

ii) For a straight line graph : The exact determination method

Step-by-step explanation:

To create lines of best fit the estimation by inspection is better than trying to determine the line of best fit exactly .

This is because line of best fit only shows the trend of the data and in most cases it doesn't have to start from origin.

Scenarios :

i) For a scatter plot : The use of estimation by inspection

ii) For a straight line graph : The exact determination method

8 0
3 years ago
Make x subject of the formula in y=2x+p​
zaharov [31]

Answer:

(y-p)/2

Step-by-step explanation:

take p to the left side. + p becomes - p. Now divide the whole thing by 2

8 0
3 years ago
Read 2 more answers
100 points for correct answer
Tems11 [23]

Answer:

\dfrac{x}{3}+\dfrac{3}{y}

Step-by-step explanation:

<u>Given fraction</u>:

\dfrac{xy+9}{3y}

\textsf{Apply the fraction rule} \quad \dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}:

\implies \dfrac{xy}{3y}+\dfrac{9}{3y}

Rewrite 9 as 3 · 3:

\implies \dfrac{xy}{3y}+\dfrac{3 \cdot 3}{3y}

Cancel the common factor y in the first fraction and the common factor 3 in the second fraction:

\implies \dfrac{x\diagup\!\!\!\!y}{3\diagup\!\!\!\!y}+\dfrac{\diagup\!\!\!\!3 \cdot 3}{\diagup\!\!\!\!3y}

\implies \dfrac{x}{3}+\dfrac{3}{y}

7 0
1 year ago
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