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dsp73
3 years ago
11

Analyze the diagram below and complete the instructions

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Hope this helped! Please let me know if I'm wrong!

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Translate into an equation or inequality to solve: Two more than twice the sum of a number and 12 is greater than the difference
tamaranim1 [39]
Let say the number is 0.5
Then, sum of this number will be 0.5+0.5=1
Now two is twice of 1.
Hence, it proved to be correct.
And difference between 5 and 1 is 4 which is less than 12. It also match the question condition.

Answer: The number is 1.
3 0
2 years ago
The tax on a $400 painting is $34 what should be the tax on a $700 painting
MAXImum [283]
$136 is the answer i think...
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3 years ago
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Sever21 [200]
Rupees 937.36

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4 0
2 years ago
HELPPPPP Find the missing parts of the triangle. Round to the nearest tenth when necessary or to the nearest minute as appropria
Romashka-Z-Leto [24]

The missing parts of the triangle ABC are A = 31.4°, B = 57.4°, C = 91.2°

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that a = 8.6 in, b = 13.9 in. and c = 16.5 in. Using cosine rule:

c² = a² + b² - 2abcosC

16.5² = 8.6² + 13.9² - 2(8.6)(13.9) * cosC

C = 91.2°

Also:

a² = b² + c² - 2bccosA

8.6² = 16.5² + 13.9² - 2(16.5)(13.9) * cosA

A = 31.4°

A + B + C = 180° (angles in a triangle)

31.4 + B + 91.2 = 180

B = 57.4°

The missing parts of the triangle ABC are A = 31.4°, B = 57.4°, C = 91.2°

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0
1 year ago
Determine whether the series is convergent or divergent. 1 4 + 3 16 + 1 64 + 3 256 + 1 1024 + 3 4096 +
Alla [95]

This series converges.

S=\dfrac14+\dfrac3{16}+\dfrac1{64}+\dfrac3{256}+\dfrac1{1024}+\cdots

S=\left(\dfrac34+\dfrac3{16}+\dfrac3{64}+\dfrac3{256}+\dfrac3{1024}+\cdots\right)-\left(\dfrac12+\dfrac1{32}+\dfrac1{512}+\cdots\right)

S=\displaystyle\sum_{n=1}^\infty\frac3{4^n}-\sum_{n=0}^\infty\frac1{2^{4n+1}}

Both component series are geometric with ratios less than 1, so they both converge.

\displaystyle\sum_{n=1}^\infty\frac3{4^n}=1

\displaystyle\sum_{n=0}^\infty\frac1{2^{4n+1}}=\frac12\sum_{n=0}^\infty\frac1{16^n}=\frac8{15}

So we have

S=\dfrac7{15}

8 0
3 years ago
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