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Marrrta [24]
3 years ago
12

NEED ANSWERS!!!

Mathematics
1 answer:
Finger [1]3 years ago
3 0

Answer:

Will earn $74.38 in interest or for the total $924.38 for the total amount accrued, principal plus interest

Step-by-step explanation:

I = p x rt

I = 850 x 0.035 x 2.5 = 74.38    (interest)

P' = p + I = 850 + 74.38 = 924.38

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Express the complex number in trigonometric form. -6 + 6 square root of 3 i ?
bagirrra123 [75]
\bf \begin{array}{clclll}
-6&+&6\sqrt{3}\ i\\
\uparrow &&\uparrow \\
a&&b
\end{array}\qquad 
\begin{cases}
r=\sqrt{a^2+b^2}\\
\theta =tan^{-1}\left( \frac{b}{a} \right)
\end{cases}\qquad r[cos(\theta )+i\ sin(\theta )]\\\\
-------------------------------\\\\

\bf r=\sqrt{(-6)^2+(6\sqrt{3})^2}\implies r=\sqrt{36+(6^2\cdot 3)}\implies r=\sqrt{144}
\\\\\\
r=12\leftarrow 
\\\\\\
\theta =tan^{-1}\left( \frac{6\sqrt{3}}{-6} \right)\implies \theta =tan^{-1}\left( -\sqrt{3}\right)\implies \theta =
\begin{cases}
\frac{2\pi }{3}\leftarrow \\
\frac{5\pi }{3}
\end{cases}

now, notice, there are two valid angles for such a tangent, however, if we look at the complex pair, the "a" is negative and the "b" is positive, that means, "x" is negative and "y" is positive, and that only occurs in the 2nd quadrant, so the angle is in the second quadrant, not on the fourth quadrant.

thus         \bf 12\left[cos\left( \frac{2\pi }{3} \right) +i\ sin\left( \frac{2\pi }{3} \right) \right]
5 0
3 years ago
Plz solve this question. you don't have to solve step by step but just give me some hints​
levacccp [35]

Answer:

u have to use derieved form of formula of sin and cos

8 0
3 years ago
What is the value of u and v?
Novay_Z [31]

Answer and Explanation:

Since this is an isosceles right triangle, you can use the ratio of side lengths specific to this type of triangle where both legs are the hypotenuse over root 2:

u = v = 164√2 / √2 = 164

so:

u = 164

v = 164

3 0
2 years ago
Read 2 more answers
Identify vertex and y-intercept of graph of function y= -3(x+2)^2+5
Doss [256]
Hello,

Vertex=(-2,5)
x=0==>y=-3(0+2)²+5=-7

3 0
3 years ago
At a local election there were two propositions on the ballot, R and S. Twice as many voters voted "yes" for R as for S. If the
Over [174]

Answer:

c. 130

Step-by-step explanation:

Let call B the quantity of voters who voted yes for both propositions.

From the question we know that twice as many voters voted "yes" for R as for S, that can be written as the following equation:

R+B=2(S+B)

Where R is the number who voted "yes" for R but "no2 for S and S is the number who voted "yes" for S but "no" for R.

Replacing R by 750 and S by 310 and solving for B, we get:

750+B=2(310+B)

750+B=620+2B

2B-B=750-620

B=130

So, 130 voters voted yes for both propositions

7 0
3 years ago
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