Suppose the depth of the diver is d at time time t, rate is given by r=12 1/3 ft/ min. The equation representing the depth of the diver at time t will be:
f(t)=200-(12 1/3)t
Therefore the depth of the diver after t=4.5 min will be:
f(4.5)=200-(12 1/3)*4.5
f(4.5)=200-55.5
f(4.5)=144.5 ft
This means that after 4.5 minutes the diver will be 144.5 ft deep.
Answer:
b = -33, -34, -35, -36, -37, etc...
Step-by-step explanation:
Answer:
x = ± 2
Step-by-step explanation:
Given
12 - x² = 0 ( add x² to both sides )
12 = x² or
x² = 12 ( take the square root of both sides )
x = ±
= ± 
= ± 2
F(x) = x^2 - 6x + 4 {-3, 0, 5} (x, y) x is the domain, y is the range.
plug in the domain numbers into the equation to find the range.
y = x^2 - 6x + 4
y = -3^2 - 6(-3) + 4
y = 9 - (-18) + 4
y = 9 + 18 + 4
y = 31 (-3, 31)
y = x^2 - 6x + 4
y = 0^2 - 6(0) + 4
y = 0 - 0 + 4
y = 4 (0, 4)
y = x^2 - 6x + 4
y = 5^2 - 6(5) + 4
y = 25 - 30 + 4
y = -1 (5, -1)
c. {-1, 4, 31}
hope this helped, God bless!
Well i may be wrong but is jack dropped it 3 feet above that wouldnt count as part of the depth the depth would start once it hits the water. so 14-3 equals 11. the depth is 11 feet. 11 is an integer. if that makes sence
