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Anarel [89]
3 years ago
15

when a boy complete 5 rounds around circular pond, he covers a distance of 1100 m. i)Find the perimeter of the pond.​

Mathematics
2 answers:
Law Incorporation [45]3 years ago
8 0
I think it’s 220m. Since 5 rounds are equal to 1100m then you divide by 5 to see how much he covers in one
Ludmilka [50]3 years ago
8 0

The perimeter of circular pond is 1100 m

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3 1/2x +4 1/3=7 2/9 does anyone know how to do this?????
saw5 [17]
I hope this helps you

5 0
3 years ago
Question Help A manufacturer ships toasters in cartons of 1010. In each​ carton, they estimate a 1010​% chance that any one of t
natta225 [31]

Answer:

The probability that there will be repair exactly 3 toaster is 0.0574.

Step-by-step explanation:

Binomial Distribution:

A discrete random variable X having the set {0,1,2,3......,n} as the spectrum, is said have a binomial distribution with parameter n= number of trials and p=probability of number of success on an individual trial, if the p.m.f (probability mass function) of X given by,

P(X=x)=C(n,x)p^x(1-p)^{n-x}    x=0,1,2,......,n

               =0                                   elsewhere

where 0<p<1 and n is a positive integer.

Total number of toaster in cartons(n) = 10.

Probability of number of success on an individual trial p= 10% = 0.10

\therefore P(X=3)= C(10,3)(0.10)^3(1-0.10)^{10-3}

                    =\frac{10!}{3!(10-3)!}(0.10)^3)(0.90)^7

                    =0.0574

The probability that there will be repair exactly 3 toaster is 0.0574.

6 0
3 years ago
"unable to determine because x can't take on the value 5.5"
Doss [256]
                    k
   f(x) = -------------------
                x - (5.5)

is an example where there's no finite limit if x approaches 5.5.
7 0
3 years ago
A right triangle has a leg of 11 cm and a hypotenuse of 17 cm.
nordsb [41]
A^2 + b^2 = c^2
11^2 + b^2 = 17^2
121 + b^2 = 289
b^2 = 289-121= 168
b = 13.0 cm
3 0
3 years ago
Read 2 more answers
What is the equation of the oblique asymptote?<br> h(x) = x² – 3x - 4/x + 2
NNADVOKAT [17]

Simplifying h(x) gives

h(x) = (x² - 3x - 4) / (x + 2)

h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)

h(x) = ((x + 2)² - 7x - 8) / (x + 2)

h(x) = ((x + 2)² - 7 (x + 2) - 14 - 8) / (x + 2)

h(x) = ((x + 2)² - 7 (x + 2) - 22) / (x + 2)

h(x) = (x + 2) - 7 - 22/(x + 2)

h(x) = x - 5 - 22/(x + 2)

An oblique asymptote of h(x) is a linear function p(x) = ax + b such that

\displaystyle \lim_{x\to\pm\infty} h(x) - p(x) = 0

In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.

4 0
2 years ago
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