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3 years ago

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Standard form: y=-3x^2-6x+1Vertex form: y=-3(x-1)^2+4Factored form: ?

1 answer:

denis-greek [22]3 years ago

7 0

Answer:

y= (2-√3x+√3)(2+√3x-√3)

Step-by-step explanation:

hello:

use identity : a²-b²=(a-b)(a+b)

y=-3(x-1)^2+4 = 2²- (√3(x-1))²= 2²-(√3x-√3)² = (2-√3x+√3)(2+√3x-√3)

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i) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(f\circ g)=f(g(x))$

$(f\circ g)=f(x^2)$

We plug in $x^2$ into $f(x)=5x-2$

$(f\circ g)=5x^2-2$

ii) Given $f(x)=5x-2$ and $g(x)=x^2$ .

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We plug in $5x-2$ into $g(x)=x^2$

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i) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

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$(h\circ g)=h(x^2-4)$

We plug in $x^2-4$ into $h(x)=\sqrt{2x+1}$

$(h\circ g)=\sqrt{2(x^2-4)+1}$

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$(g\circ h)=g(\sqrt{2x+1})$

We plug in $\sqrt{2x+1$ into $g(x)=x^2-4$

$(g\circ h)=(\sqrt{2x+1})^2-4$

$(g\circ h)=2x+1-4$

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QUESTION 3

i) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

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$(g\circ h)=g(\sqrt{x-4})$

We plug in $\sqrt{x-4}$ into $g(x)=x+5$

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We plug in $x+5$ into $g(x)=x+5$

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Step-by-step explanation:

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