F(2)= (2)+1/4(2)-2
F(2)=3/6
F(2)= 1/2
By <span>(x + 5/x^2 + 9x + 20) you apparently meant the following:
x+5
----------------------
x^2 + 9x + 20
and by
</span><span>(x^2-16/x-4)
x^2-16
you apparently meant ---------------
x - 4
Please use additional parentheses for clarity.
Dividing,
</span> x+5 (x-4)(x+4)
---------------------- * ---------------
x^2 + 9x + 20 x-4
Now, x^2 + 9x + 20 factors into (x+4)(x+5), so what we have now is
(x+5)(x+4)
------------------------- = 1 This is true for all x, so there are no exclusions.
(x+4)(x+5)
It is often more convenient to evaluate a polynomial when it is written is "Horner form."
... f(x) = (((10x -4)x -8)x +3)x -6
The graphs offered can be distinguished by their values of f(1) and f(2), so our table can be a short one.
... f(1) = (((10·1 -4)1 -8)1 +3)1 -6 = -5 . . . . . . . eliminates graph d
... f(2) = (((10·2 -4)2 -8)2 +3)2 -6 = 96 . . . . eliminates graphs a and c
The appropriate choice is b.
1. -48v-5/45 2.44-r/2 3. x=2