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3 years ago

The sum of three consecutive odd integers is 195195. what are the integers?

Mathematics

1 answer:

victus00 [196]3 years ago

6 0

195195/3 = 65065

so 65064+65065+65066 = 195195

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If 3x - 2y = 9 , 27x³- 8y³= 1377 , prove that xy = 4 plzz answer this question...

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Step-by-step explanation:

Here we are given that , the Value of

$3x - 2y = 9$
$27x^3 - 8y^3 = 1377$

And we need to find the prove that ,

$xy = 4$

We know a identity as ,

$(a-b)^3 = a^3-b^3-3ab(a-b)$

On cubing both sides of the given equation,

$(3x-2y)^3 = 9^3$

Simplify and then substitute ,

$27x^3-8y^3 -3(3x)(2y)(3x-2y ) = 729$

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$xy =\dfrac{648}{162}$

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$\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}$

Step-by-step explanation:

$5x^2-x^2e^{2x}+2e^{2x}=10$

$Let:\ x^2=t \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}$

Prologarithmize both parts of the equation:

$ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\$

Divide both parts of the equation by 2:

$\displaystyle\\x=\frac{ln5}{2}$

$t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}$

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1 year ago

The sum of three consecutive odd integers is 195195. what are the​ integers?

The sum of three consecutive odd integers is 195195. what are the integers?