Answer:
1200
Step-by-step explanation:
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Answer:
Last option 30°
damm sure about it
Step-by-step explanation:
value of x is 23 but value of Angle ABC will be x +7 i.e. 30
Answer: 1,365 possible special pizzas
Step-by-step explanation:
For the first topping, there are 15 possibilities, for the second topping, there are 14 possibilities, for the third topping, there are 13 possibilities, and for the fourth topping, there are 12 possibilities. This is how you find the number of possible ways.
15 * 14 * 13 * 12 = 32,760
Now, you need to divide that by the number of toppings you are allowed to add each time you add a topping.
4 * 3 * 2 * 1 = 24
32,760 / 24 = 1,365
There are 1,365 possible special pizzas
In order to find the vector that points from A to B we need to subtract each component of A from the corresponding component of B, according to the formula:
v(a→b)=(b1−a1,b2−a2)
In this case we have :
v(a→b)=(−5−(−8),3−(−1))
<span>v(a→b)=(3,4)
</span>To find the magnitude we use the formula:
||v|= √(v1^2)+(v1^2)
So:
||v|= √(32)+(42)
||v|= √9+16
||v|= <span>√</span>25
||v|= 5
Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.
<h3>What is the hypergeometric distribution formula?</h3>
The formula is:
The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem:
- There are 12 bulbs, hence N = 12.
- 3 are defective, hence k = 3.
The third defective bulb is the fifth bulb if:
- Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
- The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.
Hence:
0.2182 x 1/8 = 0.0273.
0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394