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RUDIKE [14]
3 years ago
10

HELP PLEASE DUE 3 MINUTES HELP

Physics
1 answer:
Elena-2011 [213]3 years ago
8 0

Answer:

Mechanical weathering breaks rocks into smaller pieces without changing their composition. ... Chemical weathering breaks down rocks by forming new minerals that are stable at the Earth's surface. Water, carbon dioxide, and oxygen are important agents of chemical weathering.

Explanation:

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Consider the following situations: i. A ball moving at speed v is brought to rest ii. The same ball starts at rest and is projec
tatyana61 [14]

Answer:

c. Case iii

Explanation:

the ball will experience the largest change in case iii

3 0
3 years ago
A girl weighing 45kg is standing on the floor, exerting a downward force of 200N on the floor. The force exerted on her by the f
sukhopar [10]

Answer:

c.

Equal to 200 N..........

7 0
3 years ago
CAN U HELP PLZZ? ;(
Ahat [919]
Answer would be D sorry if wrong
7 0
3 years ago
Electromagnetic radiation of 5.16Ă—1016 Hz frequency is applied on a metal surface and caused electron emission. Determine the w
IgorC [24]

Answer:

Work function of the metal, W_o=3.38\times 10^{-17}\ J

Explanation:

We are given that  

Frequency of the electromagnetic radiation,  f=5.16\times 10^{16} Hz

The maximum kinetic energy of the emitted electron, K=4.04\times 10^{-19}\ J

We need to find the work function of the metal.

We know that the maximum kinetic energy of ejected electron

K=h\nu-w_o

Where h=Plank's constant=6.63\times 10^{-34} J.s

\nu =Frequency of light source

w_o=Work function

Substitute the values in the given formula  

Then, the work function of the metal is given by :

W_o=h\nu -K

W_o=6.63\times 10^{-34}\times 5.16\times 10^{16}-4.04\times 10^{-19}

W_o=3.38\times 10^{-17}\ J

So, the work function of the metal is 3.38\times 10^{-17}\ J. Hence, this is the required solution.

8 0
3 years ago
A gas expands when 606 j of energy is added to it as heat. the expanding gas does 418 j of work on its surroundings.
KIM [24]
A)
 Q=606 J 
<span> W = 418 J 
</span><span> From first law of thermodynamics, 
</span><span> [ Uf - Ui ] = Q - W 
</span><span> [ Uf - Ui ]=606 -418=188 J 
</span><span> [ Uf - Ui ]= 188 J 
</span><span> 
b )
 W2 = 1212 J 
</span><span> Q2 = ? 
</span><span> Ui2=Uf =Ui +188
</span><span> Uf2=Ui
</span> [ Uf2 - Ui2 ]<span>=Ui-(Ui+188)
</span><span> -188 J 
</span><span> Q2=W2+(Uf2 -Uf1) 
</span><span> Q2 =1212 -188=1024 J 
</span><span> Q added in second step (b) so that internal energy is equal to initial internal energy of step (a)=1024 J</span>

6 0
3 years ago
Read 2 more answers
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