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Aleonysh [2.5K]
3 years ago
10

10^-1 phones in microphones

Physics
1 answer:
Arada [10]3 years ago
4 0
1 microphone = (presumably)  10⁻⁶ phone

1 phone = (presumably)  10⁶  microphones

(10⁻¹) phone  =  (presumably)  (10⁻¹) x (10⁶ microphones)

                       =       10⁵ microphones.
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How do transverse wave particles move?
Elena-2011 [213]
The answer is B the transverse waves move perpendicular to the direction the wave travels.
3 0
3 years ago
When two point charges are a distance dd part, the electric force that each one feels from the other has magnitude F.F . In orde
Harman [31]

Answer:

In order to make this force twice as strong, F' = 2 F, the distance would have to be changed to half i.e. r' = r/2.

Explanation :

The electric force between two point charges is directly proportional to the product of charges and inversely proportional to the square of the distance between charges. It is given by :

F=\dfrac{kq_1q_2}{r^2}

r is the separation between charges  

F\propto \dfrac{1}{r^2}

r=\sqrt{\dfrac{1}{F}}

If F'= 2F

r'=\dfrac{1}{\sqrt{2F} }

In order to make this force twice as strong, F' = 2 F, the distance would have to be changed to half i.e. r'=\dfrac{1}{\sqrt{2F} }. Hence, this is the required solution.                                                                                    

6 0
3 years ago
A stationary 500 kg tank fires a 20 kg miegile at 100 m/s. What is the velocity of the tank after the missile is fired? Assume t
dedylja [7]

Answer:

v₁ = 4 [m/s].

Explanation:

This problem can be solved by using the principle of conservation of linear momentum. Where momentum is preserved before and after the missile is fired.

P=m*v

where:

P = linear momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

(m_{1}*v_{1})=(m_{2}*v_{2})

where:

m₁ = mass of the tank = 500 [kg]

v₁ = velocity of the tank after firing the missile [m/s]

m₂ = mass of the missile = 20 [kg]

v₂ = velocity of the missile after firing = 100 [m/s]

(500*v_{1})=(20*100)\\v_{1}=2000/500\\v_{1}=4[m/s]

8 0
3 years ago
Gravity accelerates any object falling at 9.8 m/s2. What is the force that will be applied to the ground if an 88 kg box falls f
saw5 [17]

Answer:

The force is of the weight <u>862,4 Newtons.</u>

<u></u>

Explanation:

We have the formula:

w = m * g

Data:

w = weight = ¿?

m = mass = 88 kg

g = gravity = 9,8 m/s

Replacing according formula:

w = 88 kg * 9,8 m/s

Resolving:

w = 862,4 N

6 0
3 years ago
What is used as evidence for sea-floor spreading?
raketka [301]

Answer:

Sea-floor spreading occurs in the oceanic ridges. In there, volcanic activity, together with the gradual movement of the bottom, form new oceanic crust. This allows a better understanding of the continental drift explained by the theory of plate tectonics.

The greatest evidence for Sea-floor spreading is the oceanic trenches, the oceanic ridges, the magma protruding to the surface and the new seafloor.

In previous theories,  continents were assumed to be transported across the sea. Harry Hess, in the 1960s, proposed the idea that the seabed itself moves  as it expands from a central point. The theory is now accepted, and the phenomenon is thought to be caused by convection currents in the upper layer of the mantle.

4 0
4 years ago
Read 2 more answers
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