Answer:
0.05
Step-by-step explanation:
There are five letters to choose from. Since there is no repetition, you can choose one of 5 for the first letter, one of four for the second letter, etc. The total number of five-letter codes is
5 * 4 * 3 * 2 * 1 = 120
Now we need to find out the number of codes that start with M and end with E.
The first position is occupied by M. There is one single letter that can be placed there. The last position is occupied by E. There is a single letter that goes there. There are 3 letters left.
1 * 3 * 2 * 1 * 1 = 6
There are 6 codes that start with M and end with E
p(code that starts with M and ends with E) = 6/120 = 0.05
Answer:
I think its B.) not completely sure but i think so !!!!:)
PEMDAS
1. Parenthesis first
5 + 2 = 7
2. Exponents
7^2 = 49
49 = 49
Hope that helps!!!
Answer:
$2160
Step-by-step explanation:
=PRN
6000×0.12×3