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laiz [17]
3 years ago
10

4# is a two digit number ,where # represents the digit at ones place . 7999 ÷ 4# lies between ---------

Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:

7999 \div 4\# lies between 163.245 and 199.975

Step-by-step explanation:

Given

2 digit = 4#

Required

The range of 7999 \div 4\#

Let

\# = 0 --- the smallest possible value of #

So:

7999 \div 40 = 199.975

Let

\# = 9 --- the largest possible value of #

So:

7999 \div 49 = 163.245

<em>Hence, </em>7999 \div 4\#<em> lies between 163.245 and 199.975</em>

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Step-by-step explanation:

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Last year, a farmer harvested 3 tons of strawberries. This year, the harvest was 20% more. How many tons of strawberries did the
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Step-by-step explanation:

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What is 100,000 written as a power with a base of 10? ANSWER QUICK
DochEvi [55]

Answer:

Its either 10 to the power of 6 or ten to the power of 5

Step-by-step explanation:

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3 years ago
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Suppose that P(n) is a propositional function. Determine for which improper subset of the domain of n the statement P(n) must be
Alinara [238K]

Answer:

a) P(n) is true for all 'n' in the set ; { 0,2,4,6,8 ….. }

b) P(n) is true for all 'n' in the set ; { 0,1,2,3,4,5 ............ }

Step-by-step explanation:

a) As P(0) is true

we will assume that

  • P(2) is true
  • P(4) is true
  • P(6) is true

this simply means  that ;  P(n) is true for all 'n' in the set

{ 0,2,4,6,8 ….. }

b) since P(0) and P(1) are true

we will assume that

  • P( 0+2 ) = P(2)  is true

also P(1) and P(2) are true

we will assume that

  • P(1+2) = P(3)  is true

Also from the previous answers it can be seen that P(2) + P(3) is true

we will assume

  • P(2+2) = P(4)  is true

This simply means that P(n) is true for all 'n' in the set

{ 0,1,2,3,4,5 ............ }

8 0
2 years ago
Help! <br> Which expression is equivalent? <br> On edge
Ira Lisetskai [31]

Answer: Choice B

x^{1/8}y^{8}

======================================================

Explanation:

The two rules we use are

(a*b)^c = a^c*b^c

(a^b)^c = a^{b*c}

When applying the first rule to the expression your teacher gave you, we can say that:

\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}

Then applying the second rule lets us say

\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}

Therefore,

\left(x^{1/4}y^{16}\right)^{1/2}  = x^{1/8}y^{8}

-------------

In short, we just multiplied each exponent inside by the outer exponent 1/2.

So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.

7 0
3 years ago
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