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3 years ago

4# is a two digit number ,where # represents the digit at ones place . 7999 ÷ 4# lies between ---------

Mathematics

1 answer:

Hitman42 [59]3 years ago

4 0

Answer:

$7999 \div 4\#$ lies between 163.245 and 199.975

Step-by-step explanation:

Given

2 digit = 4#

Required

The range of $7999 \div 4\#$

Let

$\# = 0$ --- the smallest possible value of #

So:

$7999 \div 40 = 199.975$

Let

$\# = 9$ --- the largest possible value of #

So:

$7999 \div 49 = 163.245$

Hence, $7999 \div 4\#$  lies between 163.245 and 199.975

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Step-by-step explanation:

a) As P(0) is true

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2 years ago

Help! Which expression is equivalent? On edge

Ira Lisetskai [31]

Answer: Choice B

$x^{1/8}y^{8}$

======================================================

Explanation:

The two rules we use are

$(a*b)^c = a^c*b^c$

$(a^b)^c = a^{b*c}$

When applying the first rule to the expression your teacher gave you, we can say that:

$\left(x^{1/4}y^{16}\right)^{1/2} = \left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2}$

Then applying the second rule lets us say

$\left(x^{1/4}\right)^{1/2}*\left(y^{16}\right)^{1/2} = x^{1/4*1/2}*y^{16*1/2} = x^{1/8}y^{8}$

Therefore,

$\left(x^{1/4}y^{16}\right)^{1/2} = x^{1/8}y^{8}$

-------------

In short, we just multiplied each exponent inside by the outer exponent 1/2.

So that explains why the exponents go from {1/4,16} to {1/8,8} for x and y in that exact order.

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3 years ago